Answer:
The distance between the airplane and the airport is:
![c=6.64\: miles](https://tex.z-dn.net/?f=c%3D6.64%5C%3A%20miles)
Step-by-step explanation:
We can use the Pythagoras theorem to find the distance from the airplane to the airport.
The equation is:
![c^{2}=a^{2}+b^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D%3Da%5E%7B2%7D%2Bb%5E%7B2%7D)
Where:
- <u>a represents the elevations of the airplane (15000 feet)</u>
- <u>b is the distance from the ground directly below the airplane to the airport (6 miles)</u>
- <u>c is the distance between the airplane and the airport.</u>
We need first to convert 15000 feet in miles.
![15000\: feet \times \frac{0.00019\: miles}{1\: feet}=2.85\: miles](https://tex.z-dn.net/?f=15000%5C%3A%20feet%20%5Ctimes%20%5Cfrac%7B0.00019%5C%3A%20miles%7D%7B1%5C%3A%20feet%7D%3D2.85%5C%3A%20miles)
Therefore, c will be:
![c^{2}=a^{2}+b^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D%3Da%5E%7B2%7D%2Bb%5E%7B2%7D)
![c=\sqrt{a^{2}+b^{2}}](https://tex.z-dn.net/?f=c%3D%5Csqrt%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%7D)
![c=\sqrt{2.85^{2}+6^{2}}](https://tex.z-dn.net/?f=c%3D%5Csqrt%7B2.85%5E%7B2%7D%2B6%5E%7B2%7D%7D)
![c=6.64\: miles](https://tex.z-dn.net/?f=c%3D6.64%5C%3A%20miles)
I hope it helps you!
16 Pints
if that's what your asking
9514 1404 393
Answer:
(b) AB overbar congruent to CD overbar
Step-by-step explanation:
AB with an overbar is the way that <em>line segment AB</em> is designated, where appropriate typesetting is possible. Thus the statement the line segments are congruent is fully equivalent to ...
AB overbar congruent to CD overbar
12c-4=14c-10
+4 +4
12c=14c-6
-14 -14
-2c=-6
/-2 /-2
c=3
F(x) = 1.5x + 50
if you use 5GB per month, you should pay
f(5) = 1.5(5) + 50 = $57.50