The equation of a line is defined by: y=mx+b
Step 1: Find the slope (rise over run) so, the rise is 15.7 and the run is 6. 15.7/6=2.62
y=2.62x+b
Step 2: Find the b value (y intercept) - this is where the line goes through the y axis. In this case, it's 15.7
Step 3: add the slope and the b value together - y=2.62x+15.7
O get the Least Common Multiple (LCM) of 15 and 8 we need to factor each value first and then we choose all the factors which appear in any column and multiply them:
<span><span>15: 35</span><span>8: 222 </span><span>LCM: 22235</span></span>
<span>The Least Common Multiple (LCM) is: 2 x 2 x 2 x 3 x 5 = 120</span>
Answer:
Ix - 950°C I ≤ 250°C
Step-by-step explanation:
We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.
And that this temperature is x.
This means that the minimum value of x is 700°C while maximum of x is 1200 °C
Let's find the average of the two temperature limits given:
x_avg = (700 + 1200)/2 =
x_avg = 1900/2
x_avg = 950 °C
Now let's find the distance between the average and either maximum or minimum.
d_avg = (1200 - 700)/2
d_avg = 500/2
d_avg = 250°C.
Now absolute value equation will be in the form of;
Ix - x_avgI ≤ d_avg
Thus;
Ix - 950°C I ≤ 250°C
<u>ANSWER:
</u>
Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%
<u>SOLUTION:
</u>
Given,
P = RS 2000
C.I = RS 2315.35
T = 3 years
We need to find the rate per annum. i.e. R = ?
We know that,
When interest is compound Annually:
Where p = principal amount
r = rate of interest
n = number of years
![$1+\frac{R}{100}=\sqrt[3]{1.157}$](https://tex.z-dn.net/?f=%241%2B%5Cfrac%7BR%7D%7B100%7D%3D%5Csqrt%5B3%5D%7B1.157%7D%24)
R = 5%
Hence, rate per annum is 5 percent.
