Answer:
hope this helps and do consider giving a brainliest to the ans if it helped.
Explanation:
//program to check if the entered grid is magic square or not
/**c++ standard libraries
*/
#include<bits/stdc++.h>
using namespace std;
/**function to check whether the entered grid is magic square or not
*/
int isMagicSquare(int arr[3][3]){
int i,j,sum=0,sum1=0,rsum,csum;
for(i=0;i<3;i++){
sum+=arr[i][i];
sum1+=arr[i][2-i];
}
if(sum!=sum1){
return 0;
}
for(i=0;i<3;i++){
rsum=0;
csum=0;
for(j=0;j<3;j++){
rsum+=arr[i][j];
csum+=arr[j][i];
}
if(sum!=rsum){
return 0;
}
if(sum!=csum){
return 0;
}
}
return 1;
}
/** main function to get user entries and
* call function
* and print output
*/
int main(){
int i,j,arr[3][3]={0};
for(i=0;i<3;i++){
for(j=0;j<3;j++){
cout<<"Enter the number for row "<<i<<" and column "<<j<<" : ";
cin>>arr[i][j];
}
}
int ret = isMagicSquare(arr);
if(ret==1){
cout<<"This is a Lo Shu magic square"<<endl;
}
else{
cout<<"This is not a Lo Shu magic square"<<endl;
}
return 0;
}
I think it should be in the design tab
Answer:
Variable, operator, expression, value.
Explanation:
We could use variables, operators, expressions, and values in a mathematical formula, we're going to do an example with every part.
For this example we're going to use a simple sum formula:
First, we have 3 variables:
sum;
sum1;
sum2;
Second, we have 3 operators:
=, + and *
Third, we have our expression and 1 value:
sum = sum1 + (sum2 * 5);
(sum2 * 5) = expression;
5 = value;
We're going to see the result when we print the variable sum.
Database is were servers are on server hold ip adress spread sheets hold datd
it is spread sheet
