Answer:
y=-1/2x+3/2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-1-1)/(5-1)
m=-2/4
m=-1/2
y-y1=m(x-x1)
y-1=-1/2(x-1)
y=-1/2x+1/2+1
y=-1/2x+1/2+2/2
y=-1/2x+3/2
Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Answer:
b
Step-by-step explanation: