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zysi [14]
3 years ago
14

Which of the following is an example of an open equation?

Mathematics
1 answer:
djyliett [7]3 years ago
8 0
Which of the following is an example of an open equation?
An open equation is an equation with at least one variable.
Therefore, 5x + 7 = 12 is an open equation.

Which of the following equations has 3 as a solution
z ‒ 15 = ‒12
z = -12 + 15 = 3

Is (1, 5) a solution to the equation y = x – 2?
5 ≠ 1 - 2
-5 ≠ -1
no

Is (–2, –6) a solution to the equation y = 3x?
-6 = 3(-2)
yes

Which of (3, 5), (4, 6), (5, 7), and (6, 8) are solutions to y = x + 2
5 = 3 + 2
6 = 4 + 2
7 = 5 + 2
8 = 6 + 2
all

Which equation would be used to generate the data in the following table?
x y
1 8
2 16
3 24
4 32
y = 8x

On a treadmill, you burn 11 calories in 1 minute, 22 calories in 2 minutes, 33 calories in 3 minutes, and so on. How many calories do you burn in 10 minutes?
11 x 10 = 110 calories
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Which two values of X are roots of the polynomial below 4x^2-6x+1
PtichkaEL [24]

4x^2-6x+1=0\\\\a=4,\ b=-6,\ c=1\\\\\Delta=b^2-4ac\\\\\Delta=(-6)^2-4(4)(1)=36-16=20\\\\\sqrt\Delta=\sqrt{20}=\sqrt{4\cdot5}=\sqrt4\cdot\sqrt5=2\sqrt5\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a},\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{-(-6)-2\sqrt5}{2\cdot4}=\dfrac{3-\sqrt5}{4}\\\\x_2=\dfrac{-(-6)+2\sqrt5}{2\cdot4}=\dfrac{3+\sqrt5}{4}

5 0
3 years ago
Determine the equation of the line, written in slope-intercept form, that passes through the points (1,1) and (5,−1).
bazaltina [42]

Answer:

y=-1/2x+3/2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-1)/(5-1)

m=-2/4

m=-1/2

y-y1=m(x-x1)

y-1=-1/2(x-1)

y=-1/2x+1/2+1

y=-1/2x+1/2+2/2

y=-1/2x+3/2

3 0
3 years ago
What is the surface area of the right cone below?
Nadusha1986 [10]
B) 72pie units squared
3 0
3 years ago
Will award brainliest to correct answer!
Artyom0805 [142]

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

\angle \: ABP =  \frac{180 - 80}{2}  = 50 \degree

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.

Therefore, the angle BKQ is equal to 180-50-45=85°.

Of course angle BKP=180-85=95°.

Hope this helps :)

6 0
2 years ago
Which of the following inequalities matches the graph. x&gt;-3 x&lt;-3 y&gt;-3 y&lt;-3
kvv77 [185]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
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