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rosijanka [135]
3 years ago
13

Drinks are prepared and arranged on a table for a party. The probability that a drink is grape juice is 0.3. The probability tha

t a drink has a straw is 0.3. The probability that a drink is grape juice and has a straw is 0.1. Use the addition rule to determine the probability that a drink is grape juice or has a straw. Enter your answer as a decimal, rounded to the nearest tenth, like this: 0.4
Mathematics
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

0.5

Step-by-step explanation:

P(grape or straw) = P(grape) + P(straw) − P(grape and straw)

P(grape or straw) = 0.3 + 0.3 − 0.1

P(grape or straw) = 0.5

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Solve for x: 1 1/5 x -2 1/3 < 1/7 x+ 1 1/2
Firlakuza [10]
Solving inequalities is similar to solving a regular equation. The only thing you need to worry about with inequalities is that when you are dividing or multiplying by a negative number, you must flip the inequality sign. You won't have to worry about that here if the coefficient in front of x is positive when you divide!

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- To multiply fractions, multiply the numerators and multiply the denominators. Put the product of the numerators over the product of the denominators.

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Back to the problem:
</span>You are told that 1 \frac{1}{5} x - 2 \frac{1}{3} \ \textless \ \frac{1}{7} x + 1 \frac{1}{2} and you have to solve for x.
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1) </span>Using the info for converting mixed numbers to improper fractions from above, you know that 1 \frac{1}{2} =  \frac{3}{2} and 2 \frac{1}{3} =  \frac{7}{3} and 1 \frac{1}{5} x =  \frac{6}{5} x. Now add/subtract using the info above, isolating the variable x by adding 2 \frac{1}{3} to both sides and subtracting \frac{1}{7} x from both sides. 
1 \frac{1}{5} x - 2 \frac{1}{3} \ \textless \ \frac{1}{7} x + 1 \frac{1}{2}\\&#10;\frac{6}{5} x -  \frac{7}{3} \ \textless \ \frac{1}{7} x + \frac{3}{2}\\&#10;(\frac{6}{5} x  - \frac{1}{7} x) \ \textless \ (\frac{3}{2} + \frac{7}{3})\\&#10;(\frac{42}{35} x  - \frac{5}{35} x) \ \textless \ (\frac{9}{6} + \frac{14}{6})\\&#10; \frac{37}{35} x \ \textless \   \frac{23}{6}

2) Divide both sides by \frac{37}{35} to get the inequality for x. Remember the info for dividing from above:
\frac{37}{35} x \ \textless \ \frac{23}{6}\\&#10;x \ \textless \  \frac{23}{6} \div \frac{37}{35}  \\&#10;x \ \textless \  \frac{23}{6} \times \frac{35}{37} \\&#10;x \ \textless \  \frac{805}{222}

Your final answer is x < \frac{805}{222} or x < 3 \frac{139}{222}.
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