Answer:
string1 = "this is string 1"
string2 = " this is string 2"
print(string1 + string2)
Explanation:
the string1 variable is assigned with a string value(aka. str)
string2 is also a variable assigned with a slightly different string value
the 3rd line then prints string 1 and 2 to the console.
Answer:
PART ONE
- import java.util.Scanner;
- public class CountToLimit {
- public static void main(String[] args) {
- Scanner scnr = new Scanner(System.in);
- int countLimit = 0;
- int printVal = 0;
- // Get user input
- System.out.println("Enter Count Limit");
- countLimit = scnr.nextInt();
- do {
- System.out.print(printVal + " ");
- printVal = printVal + 1;
- } while ( printVal<=countLimit );
- System.out.println("");
- return;
- }
- }
PART TWO
- import java.util.Scanner;
- public class NumberPrompt {
- public static void main (String [] args) {
- Scanner scnr = new Scanner(System.in);
- System.out.print("Your number < 100: ");
- int userInput = scnr.nextInt();
- do {
- System.out.print("Your number < 100: ");
- userInput = scnr.nextInt();
- }while (userInput>=100);
- System.out.println("Your number < 100 is: " + userInput);
- return;
- }
- }
Explanation:
In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14
In part 2, A do....while loop that will repeatedly prompt user to enter a number less than 100 is created. from line 7 to line 10
Answer:
userB will use his/her private key.
Explanation:
The steps involved in using asymmetric cryptographic algorithm are as follow:
1. Each user generates a pair of keys to be used for the encryption and decryption of messages.
2. Each user places one of the two keys in a public register or other accessible file. This is the public key. The companion key is kept private.
3. If UserA wishes to send a confidential message to UserB, UserA encrypts the message using UserB's public key.
4. When UserB receives the message, she decrypts it using her private key.
