You have 12 girls out of 32, so that's 20 boys. Take your amount of boys divided by your total number. So, 20/32 = .625
You want a percentage, so .625 x 100 = 62.5% boys
Answer:
x° is 66°
Step-by-step explanation:
From the given diagram, we have;
∠JIH = 105° Given
∠IDJ = 39° Given
Therefore, we have;
∠JID and ∠JIH are supplementary angles, by the sum of angles on a straight line
∴ ∠JID + ∠JIH = 180° by definition of supplementary angles
∠JID + 105° = 180° by substitution property
∠JID = 180° - 105° = 75° by angle subtraction postulate
∠JID = 75°
∠IDJ + ∠JID + ∠IJD = 180° by the sum of interior angles of a triangle
∠IJD = 180° - (∠IDJ + ∠JID) = 180° - (39° + 75°) = 66° angle subtraction postulate
∠IJD = 66°
∠x° ≅ ∠IJD, by vertically opposite angles
∴ ∠x° = ∠IJD = 66° by the definition of congruency
∠x° = 66°
Answer:
x = {nπ -π/4, (4nπ -π)/16}
Step-by-step explanation:
It can be helpful to make use of the identities for angle sums and differences to rewrite the sum:
cos(3x) +sin(5x) = cos(4x -x) +sin(4x +x)
= cos(4x)cos(x) +sin(4x)sin(x) +sin(4x)cos(x) +cos(4x)sin(x)
= sin(x)(sin(4x) +cos(4x)) +cos(x)(sin(4x) +cos(4x))
= (sin(x) +cos(x))·(sin(4x) +cos(4x))
Each of the sums in this product is of the same form, so each can be simplified using the identity ...
sin(x) +cos(x) = √2·sin(x +π/4)
Then the given equation can be rewritten as ...
cos(3x) +sin(5x) = 0
2·sin(x +π/4)·sin(4x +π/4) = 0
Of course sin(x) = 0 for x = n·π, so these factors are zero when ...
sin(x +π/4) = 0 ⇒ x = nπ -π/4
sin(4x +π/4) = 0 ⇒ x = (nπ -π/4)/4 = (4nπ -π)/16
The solutions are ...
x ∈ {(n-1)π/4, (4n-1)π/16} . . . . . for any integer n
I believe it would be 12 because 9 min divided by .75 a rotation gets 12 rotations
to put them together and add them.
