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mojhsa [17]
3 years ago
15

The general manager of a fast food restaurant chain must select 6 restaurants from 11 for a promotional program. How many differ

ent possible ways can this selection be done?
Mathematics
2 answers:
zmey [24]3 years ago
5 0

Answer:

462

Step-by-step explanation:

There 6 slots available to fill in the restaurants options

- For the 1st slot, there are 11 ways to choose

- For the 2nd slot, there are 10 ways to choose

- For the 3rd slot, there are 9

- For the 4th slot, there are 8

- For the 5th slot, there are 7

- For the last 6th, there are 6 ways

So in total there would be 11*10*9*8*7*6 = 332640 ways to choose. But since the order of these 6 slots don't matter, there are actually 6! = 720 ways to order these 6 slots. So the actual number of possible ways is

332640 / 720 = 462

Arisa [49]3 years ago
4 0

Answer:

Step-by-step explanation:

This question will be solved using the combination formula which is nCr because the order is unimportant and we need the selection.

11C6

11!/(11-6)!*6!

= 462

Therefore the manager can select the restaurant in 462 ways.

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10^-2 = 1/10^2 which is 0.01
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I need help on number 1
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2 years ago
of 320 consumers polled, some purchase blu-ray movies, some only purchase movies on dvd, and some do both. if 300 people polled
Helga [31]

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20 people only buy dvds.

Step-by-step explanation:

There are two groups in this problem. One group of people that buys dvds and one that buys blu rays. The total amount of people who buy blu rays is 300, but there's an intersection between the groups and the size of this is 280 people who actually buy both. In order to find out how many people only buy DVDs we first need to figure out how many only buy blu-rays. That is:

people who only buy blu rays = people who buy blu rays - people who buys blu rays and dvds

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We can now calculate the amount of people who only buy dvds and that is:

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3 0
3 years ago
Consider the following system of equations:
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The system has infinitely solutions

Step-by-step explanation:

we have

-\frac{1}{3}x^{2}=-\frac{5}{6}+\frac{1}{3}y^{2}

\frac{1}{3}x^{2}+\frac{1}{3}y^{2}=\frac{5}{6}

Multiply by 3 both sides

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and

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Equation A and Equation B are the same

Therefore

The system has infinitely solutions

7 0
3 years ago
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