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3 years ago

Can someone please explain 10 3/4 - 6 4/4 ??

Mathematics

2 answers:

xxMikexx [17]3 years ago

7 0

Answer:

43/4 - 28/4 = (43 - 28)/4 = 15/4 or 3 3/4

Step-by-step explanation:

10 3/4 - 6 4/4 . The expression means we should find the difference between 10 3/4 and 6 4/4. The best approach to find the difference of this kind of fractions with whole number is by turning each to an improper fraction.

10 3/4 . This whole number fraction can be turn to an improper fraction as follows

10 × 4 + 3 = 43 then 43/4

6 4/4. 4 × 6 + 4 = 28/4.

Now , let's find the difference

The denominator is same, which is 4

43/4 - 28/4 = (43 - 28)/4 = 15/4 or 3 3/4

motikmotik3 years ago

4 0

3 3/4 is the answer

10 3/4 --- 43/4

6 4/4--- 7 or 28/4

43/4- 28/4= 15/4

15/4 simplified is 3 3/4

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Surface area of a rectangular prism if W = 6in L = 9in and H = 2in

Delicious77 [7]

Answer:

Step-by-step explanation:

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4 0

3 years ago

Suppose you are given a cube made of magnesium (mg) metal of edge length 2.15 cm. (a) calculate the number of mg atoms in the cu

SVETLANKA909090 [29]

solution:

a) To calculate the volume of cube of edge 1.0cm

Volume= (edge)³

=(100cm) ³

= 1cm³

To find the mass of MG atoms

Density = mass/volume

Mass of mg = 1.74g/cm³ x 1cm³

= 1.74g

To find the number of mg atoms,

Molar mass of mg = 24.31g

24.31g mg contain 6.022 x 10²³ atoms of mg

1.74g mg contain = 6.022 x 10²³mg atoms/24.31g mg x 1.74g mg

= 0.4310 x 10²³mg atoms

= 4.31 x 10²² mg atoms

B) to find the volume occupied by mg atoms

Total volume of cube = 1 cm³

Volume occupied by mg atoms

= 74% of 1cm³

=74/100 x 1cm³= 0.74cm³

To find the volume of 1 mg atom

4.31 x 10²² mg atoms occupy 0.74 cm³

1 atom will occupy 0.74cm³

1 atom will occupy = 0.74cm³/4.31 x 10²²mg atoms x 1mg atom

volume of 1 mg atom = 0.1716 x 10⁻²²cm²

Volume of 1 mg atom = 4/3 π³ in the form of sphere.

4/3πr³ = 0.1716 x 10⁻²²cm³

R³ = 0.1716 x 10⁻²²cm³x 4/3 x 7/22

R³ = 0.04095 x 10⁻²²cm³

R = 0.1599 x 10⁻⁷cm

1 = 10⁻¹⁰cm

= 0.1599 x 10⁻⁷cm

= 1pm/1 x 10⁻¹⁰cm x 0.1599 x 10-7cm

= 1.599 x 10² pm

R= 1.6 x 10²pm

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3 years ago

The proof that point (1,root 3) lies on the circle that is centered at the origin and contains the point (0,2) is found in the t

AURORKA [14]

<h2>Answer:</h2>

D. Distance formula

<h2>Step-by-step explanation:</h2>

$The \ \mathbf{distance} \ d \ between \ the \ \mathbf{points} \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ in \ the \ plane \ is:\\ \\ d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

As in the statement:

<em>The distance form</em> $(0,0)$ to $(0,2)$ is $\sqrt{(0-0)^2+(2-0)^2}=\sqrt{2^2}=2$ <em>whose justification is the </em><em>Distance Formula. </em>

<em />

Here in this statement the justification is also the Distance Fromula, so we take the distance from $(0,0) \ to \ (1,\sqrt{2})$ whose result is also 2 and is the radius of the circle.