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Anestetic [448]
3 years ago
7

Given the function h(t) = (t + 3) + 4, what is h(8)?

Mathematics
2 answers:
sleet_krkn [62]3 years ago
8 0

Answer:

15

Step-by-step explanation:

    h(t) = (t + 3) + 4,

For h(8);substitute for 't' in the above equation given that

h(t)=h(8) and eliminating 'h'  on both sides  t = 8.

Hence,

h(8) = (8 + 3) + 4

h(8) = 11 + 4

h(8) = 15

MatroZZZ [7]3 years ago
6 0
H (8) = ( 8 + 3 ) 2 + 4 = ( 11 ) 2 + 4 = 22 + 4 = 26
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If p(x)=2x^3+cx^2+16x+84 and x+2 is a factor of p(x),find the value of c.
Nuetrik [128]

Answer:

c = -9

Step-by-step explanation:

Knowing that -2 is a root, you can do the synthetic division with an unknown value for c. Then solve for the value of c that makes the remainder be zero. See the attachment for the work.

The second attachment shows that (x+2) is a factor of the resulting cubic.

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3 years ago
The time a traffic light remains yellow is one second more than 0.05 times the speed limit. What is the yellow time for a traffi
weqwewe [10]
30 * 0.05 + 1 = X
1.5 + 1 = X
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The light remains yellow for 2.5 seconds on a street with a speed limit of 30.
4 0
3 years ago
12/11k÷4/3k<br><br>simplify the fraction
Nonamiya [84]

Answer:

9/11

Step-by-step explanation:

12/11k÷4/3k

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3 0
3 years ago
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Please help I only have an hour. ​
Goshia [24]

Answer:

Slope (m) = \frac{y}{x} = \frac{2}{3} = 0.66666666666667

Step-by-step explanation:

0 = arctan (\frac{y}{x}) = 33.69006752598°

X = 4 – 1 = 3

Y = 4 – 2 = 2

Distance (d) = \sqrt{x^2+y^2}= \sqrt{13} =3.605551275464

Equation of the line:

y = 0.66666666666667x + 1.3333333333333

or

y=\frac{2}{3}x+\frac{4}{3}

When x=0, y = 1.3333333333333

When y=0, x = -2

4 0
2 years ago
These roots of the polynomial equation x^4-4x^3-2x^2+12x+9=0 are 3,-1,-1. Explain why the fourth root must be a real number. Fin
Alex787 [66]

Roots with imaginary parts always occur in conjugate pairs. Three of the four roots are known and they are all real, which means the fourth root must also be real.

Because we know 3 and -1 (multiplicity 2) are both roots, the last root r is such that we can write

x^4-4x^3-2x^2+12x+9=(x-3)(x+1)^2(x-r)

There are a few ways we can go about finding r, but the easiest way would be to consider only the constant term in the expansion of the right hand side. We don't have to actually compute the expansion, because we know by properties of multiplication that the constant term will be (-3)(1)(1)(-r)=3r.

Meanwhile, on the left hand side, we see the constant term is supposed to be 9, which means we have

3r=9\implies r=3

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Other things we could have tried that spring to mind:

- three rounds of division, dividing the quartic polynomial by (x-3), then by (x+1) twice, and noting that the remainder upon each division should be 0

- rational root theorem

4 0
3 years ago
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