1) circumference= 3.14 x 12
C= 37.68
19x+12y=17
step 1: move the thing that you're looking for to the left side and all the rest to the right side:
(19x +12y)-19x = 17 -19x
12y = 17 -19x
step 2: to find y, you need to get rid of 12. to do so you need to devide everything by that number:
(12y)/12 = 17/12 -19/12 x
y= 17/12 -19/12 x
step 3: simplify of possible. ( in this exercise it isnt)
step 4: rearange the equation if necessary
y= 17/12 + -19/12x
y= -19/12x + 17/12
C is the correct answer, which is the larger the number of students Terrance surveys, better his estimate of the mean will be
![-\frac{5}{12} \ \textless \ -\frac {2}{5}](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B12%7D%20%5C%20%5Ctextless%20%5C%20-%5Cfrac%20%7B2%7D%7B5%7D)
because -2/5 is closer to 0 than -5/12
Step-by-step explanation:
it is not important that the triangle is right-angled.
but the distance between each pair of points is calculated via Pythagoras
c² = a² + b²
with c being the Hypotenuse (baseline opposite of the 90° angle) = distance between the end points, and a and b are the legs (= the x and y coordinate differences of the 2 end points) of the virtual right-angled triangles between each pair of points.
so,
AB² = (6 - -3)² + (-4 - -4)² = 9² + 0² = 81
AB = 9 ft
BC² = (6 - 6)² + (8 - -4)² = 0² + 12² = 144
BC = 12 ft
and now for AC, which is because of the special case of how the main triangle is placed and oriented, the same calculation as with Pythagoras for the main right-angled triangle. but I keep showing you the point distance calculation, because this is what you will need in the future for more general triangle or other shapes calculations :
AC² = (6 - -3)² + (8 - - 4)² = 9² + 12² = 81 + 144 = 225
AC = 15 ft
so, Nasir will need
9 + 12 + 15 = 36 ft
of fencing.