Point R is the midpoint of FE¯¯¯¯¯ , so the coordinates of point R are (3a, b).
In △DEF , the length of the base, DF¯¯¯¯¯ , is
4a, and the height is 2b, so its area is
1/2×4a×2b = 4ab.
In △QRP , the length of the base, QR¯¯¯¯¯ , is
3a-a = 2a, and the height is b, so its area is 1/2×2a×b = ab .
Comparing the expressions for the areas proves that the area of the triangle created by joining the midpoints of an isosceles triangle is one-fourth the area of the larger isosceles triangle.
Answer:
4 tiles
Step-by-step explanation:
Area of a square tile:
A = s²
A = (30)²
A = 900 cm
900 cm = 9 m
Area of the square room:
A = s²
A = (6)²
A = 36 m
36 ÷ 9 = 4
Answer:
x1=2 x2=-5
Step-by-step explanation:
Answer:
there is a 1/13 (one in 13) chance that they will randomly pick a labrador.
Step-by-step explanation: If you need more help just message me :)
Can you attach the image of the table ?
