B. $2.80
you do .8•35 then you get 28 then you move the decimal over 1
Answer:
Option C . 5.3 in
Step-by-step explanation:
<u><em>The complete question is</em></u>
An art project has an area of 63.6 square inches. What is the width, in inches, of the project?
A rectangle is shown divided into 4 smaller rectangles that are related to the size of the edges. The top edge is labeled 10 inches and 2 inches, above the top two rectangles. The top two rectangles are much larger than the bottom two rectangles
Let
x ----> the length of the art project in inches
y ----> the width of the art project in inches
we know that
The area of the rectangular art project is equal to

we have

so
----> equation A

substitute the value of x in the equation A
solve for y

You have to use the Pythagoras theorem: c² = a²+b²
You have been given the c side, the diagonal side, and the b side the height side. You need to square both of them, take them away from each other and then get the square root of that answer;
120²-64² = 10302
√10302 = 101.49
The answer is 101.49ft,
Hope this helps! :)