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natali 33 [55]
3 years ago
13

RSM HOMEWORK HELP!!!

Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0

Answer:

Step-by-step explanation:

∠CAB = 33       {alternate interior angles}

5x = 33 + 2x    { exterior angle equals sum of opposite interior angles}

5x - 2x = 33

3x = 33

x = 33/3

x = 11

∠B = 2x = 2* 11 = 22

∠ECB = 5x = 5*11 = 55

bonufazy [111]3 years ago
8 0
The answer is 21 bc 9+10=21
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The diagonals of a quadrilateral QRST intersect at P(2,3). QRST has vertices at Q(3,6) and R(-3,5). What must be the coordinates
Sergio [31]

Answer:

S (1 , 0)

T (7 , 1)

Step-by-step explanation:

If QRST is a parallelogram, P is the mid point of segment QS and segment RT.

Basic formula for mid-point of segment: ((x1+x2)/2 , (y1+y2)/2)

T (x₁ , y₁)    S (x₂ , y₂)   P (2 , 3)    Q (3 , 6)   R (-3 , 5)

2 = (x₁ + (-3))/2         x₁ = 7

3 = (y₁ + 5)/2            y₁ = 1

T (7 , 1)

2 = (x₂ + 3))/2         x₂ = 1

3 = (y₂ + 6)/2           y₂ = 0

S (1 , 0)

4 0
3 years ago
2/5 kg of soul fills 1/3 of a container so 1 kg of sulfate in the container? Explain or show your reasoning
Softa [21]

Answer:

Yes, we can put 1 kg of the soul in the container.

Step-by-step explanation:

Consider the provided information.

2/5 kg of soul fills 1/3 of a container.

It means if we put 2/5 kg of the soul 3 times in the container then the container will be full.

\frac{2}{5}+\frac{2}{5}+\frac{2}{5}=\frac{6}{5}

It means \frac{6}{5} kgs of soul fill the container.

\frac{6}{5} is greater than 1 so it means we can put 1 kg of the soul in the container.

6 0
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WITCHER [35]
I: 12x-5y=0
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with I:
12x=5y
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-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
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(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0

insert into I:
12x=0
x=0

-> only intersection is at (0,0) = option B
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