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4 years ago

A rock is thrown straight up into the air. At the

1 answer:

6 0

The answer is 3.

When a ball is thrown into the air, there is no friction (there's nothing rubbing against it), so the only force acting on the ball is gravity, which aims to pull the ball back down. Since this is the only force, the answer will equal the gravity acting on the ball. Since "weight" is defined as just that (the gravity acting on something), the answer is 3, the magnitude of the rock's weight (or the force of gravity).

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A hydraulic lift consists of two pistons that connect to each other by an incompressible fluid. If one piston has an area of 0.1

hjlf

You have:

A1= 0.15 m²
A2=6.0 m²
F1=130.0 N

To solve this problem you must use the pressure formula, as below:

P1=P2
F1/A1=F2/A2

Then, you have:

m2=A2xF1/A1xg

g=9.81 m/s² (This is the acceleration of gravity)

When you substitute the values in m2=A2xF1/A1xg, you obtain:

m2=(0.60 m² x 130.0 N)/(0.15 m² x 9.81 m/s²)

The answer is:

m2=530 Kg

5 0

4 years ago

Where is the Ring Of Fire located?

Bingel [31]

Answer:

The pacific ocean

Explanation:

because the pacific ocean is where many earthquakes and volcanic eruptions occur.

8 0

3 years ago

Read 2 more answers

Two particles move along an x axis. The position of particle 1 is given by x ! 6.00t 2 # 3.00t # 2.00 (in meters and seconds); t

s344n2d4d5 [400]

Answer:

15.6m/s

Explanation:

V1= $\frac{dx}{dt}=\frac{d}{dt}(6t^{2}+3t+2)$ because the derivate of the position is the velocity

V1=12t+3

V2=20+ $\int\limits^_ {} \,$ -8t because the integral of the acceleration is the velocity

V2= $20-4t^{2}$

V1=V2 to see when the velocities of particles match

12t+3=20-4t^2

4t^2+12t-17=0 we resolve this with $\frac{-b+-(\sqrt{b^{2} -4ac} )}{2a}$

and we take the positif root

t=1.05 sec

if we evaluate the velocity (V1 or V2) the result is 15.6m/s

7 0

3 years ago

A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 5.10 m/s

yarga [219]

Answer:

$I=336.6kgm/s$

Explanation:

The equation for the linear impulse is as follows:

$I=F\Delta t$

where $I$ is impulse, $F$ is the force, and $\Delta t$ is the change in time.

The force, according to Newton's second law:

$F=ma$

and since $a=\frac{v_{f}-v_{i}}{\Delta t}$

the force will be:

$F=m(\frac{v_{f}-v_{i}}{\Delta t})$

replacing in the equation for impulse:

$I=m(\frac{v_{f}-v_{i}}{\Delta t})(\Delta t)$

we see that $\Delta t$ is canceled, so

$I=m(v_{f}-v_{i})$

And according to the problem $v_{i}=0m/s$ , $v_{f}=5.10m/s$ and the mass of the passenger is $m=66kg$ . Thus:

$I=(66kg)(5.10m/s-0m/s)$

$I=(66kg)(5.10m/s)$

$I=336.6kgm/s$

the magnitude of the linear impulse experienced the passenger is $336.6kgm/s$

6 0

3 years ago

What are the strength and direction of an electric field that will balance the weight of a 0.9 g plastic sphere that has been ch

Vladimir79 [104]

(a) The force exerted by the electric field on the plastic sphere is equal to
$F=qE$
where $q=-3.4 nC=-3.4 \cdot 10^{-9} C$ is the charge of the sphere and E is the strength of the electric field. This force should balance the weight of the sphere:
$F=mg =0.9 g$
where m is the mass of the sphere and g is the gravitational acceleration.

Since the two forces must be equal, we have:
$qE=mg$
and so we find the intensity of the electric field
$E= \frac{mg}{q}= \frac{0.9 \cdot 9.81 m/s^2}{3.4 \cdot 10^{-9} C} =2.6 \cdot 10^9 N/C$

(b) Now let's find the direction of the field. The electric force must balance the weight of the sphere, which is directed downward, so the electric force should be directed upward. Since the charge is negative, the force is opposite to the electric field direction, and so the direction of the electric field is downward.

4 0

3 years ago