Answer:
(D) parasite........................
Answer:
Explanation:
electrical field strength = potential diff / distance
= ( 450 - 0 ) / 8 x 10⁻²
= 5625 V/m
b )
potential difference = electric field x distance
= 5625 x .10
= 562.5 V
Answer: I think the answer <em><u>MIGHT</u></em> be: Boron, germanium, and tellurium....
Explanation:I know this cuz I had this question on my unit test and I had to look it up online....Hope this helps
I really hope you guys find this helpful and thx so much for rating :D
pls say something in chat if you found this helpful
UwU ;-;
The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.
<h3>Electric field on the master charge</h3>
E = kq/r²
where;
- q is magnitude of master charge
- r is distance of separation
- k is Coulomb's constant
E = (9 x 10⁹ x 0.63)/(0.75²)
E = 1.008 x 10¹⁰ N/C
<h3>Force on the test charge</h3>
F = Eq
where;
- E is electric field
- q is the test charge
F = (1.008 x 10¹⁰) x (0.5)
F = 5.04 x 10⁹ N
Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.
Learn more about electric field here: brainly.com/question/14372859
#SPJ1
