Answer:
I believe it's called qualitative
Explanation:
Answer:

Explanation:
The difference of electric potential between two points is given by the formula
, where <em>d</em> is the distance between them and<em> E</em> the electric field in that region, assuming it's constant.
The electric field formula is
, where <em>F </em>is the force experimented by a charge <em>q </em>placed in it.
Putting this together we have
, so we need to obtain the electric force the charged ball is experimenting.
On the second drop, the ball takes more time to reach the ground, this means that the electric force is opposite to its weight <em>W</em>, giving a net force
. On the first drop only <em>W</em> acts, while on the second drop is <em>N</em> that acts.
Using the equation for accelerated motion (departing from rest)
, so we can get the accelerations for each drop (1 and 2) and relate them to the forces by writting:


These relate with the forces by Newton's 2nd Law:


Putting all together:

Which means:

And finally we substitute:

Which for our values means:

Answer:
Tension in string equals 14.715 Newtons
Explanation:
The situation is represented in the figure attached below:
For equilibrium of the clothes along y- axis we have

Applying values we get

Answer:
Explanation:
We know that
Δr = r₁ - r₀
r₀ = 0 i + 0 j
r₁ = (162+137*Cos(31º)+137*Cos(-48º)) i + (0+137*Sin(31º)+137*Sin(-48º)) j = (371.1028 i - 31.2506 j) ft
Δr = r₁ - r₀ = (371.1028 i - 31.2506 j) - (0 i + 0 j) = (371.1028 i - 31.2506 j) ft
Magnitude:
Δr = √((371.1028)²+(-31.2506)²) = 372.4163 ft
Angle:
tan θ = (- 31.2506 / 371.1028) = -0.0839 ⇒ θ = tan⁻¹(-0.0839) = - 4.8135º
(below the horizontal).
SOLUTION:
1 minute = 60 seconds
1 second = 1 metre
1 × 60 = 1 × 60
60 seconds = 60 metres
1 minute = 60 metres
Therefore, the horse can gallop / travel 60 metres in 1 minute.
Hope this helps! :)
Have a lovely day! <3