a .6 kg ball has a speed of 2 m/s at point a and kinetic energy of 7.5 j at point b. determine the following: the balls speed

A fisherman is fishing from a bridge and is using a "44.0-N test line." In other words, the line will sustain a maximum force of

vitfil [10]

Answer:

a) 4.485 kg b) 3.94 kg

Explanation:

since the maximum tension the line can stand is 44 N and for question a the speed is constant (acceleration must be zero since the velocity or speed is not changing), F(tension) = mass * acceleration due to gravity (g) .

44 = m * 9.81m/s^2

m = 44/9.81 = 4.485kg

b) F(tension) = ma + mg ( where a is the acceleration of the body and g is the acceleration of the gravity)

44 = m (a +g)

44 = m (1.37 + 9.81)

44/11.18 = m

m = 3.94 kg

3 0

3 years ago

In a LRC circuit, a second capacitor is connected in parallel with the capacitor previously in the circuit. What is the effect o

likoan [24]

Answer:

Impedance increases for frequencies below resonance and decreases for the frequencies above resonance

Explanation:

See attached file

Explanation:

3 0

3 years ago

An electric kitchen range has a total wall area of 1.40 m2 and is insulated with a layer of fiberglass 4.0 cm thick. The inside

Gemiola [76]

Answer: Heat current through the insulator=196W

Electric power= 196W

Explanation: Given: Kglass = 0.040W/m

Temperature of inside glassTi=175°C

Temperature of outside glass To= 35°C

Area=1.4m^2 , L= 4×10^-2

Heat current(H)= K ×A× (Ti - To)/L

Substituting the values into the equation

H = 0.04 × K × 1.4 ×(175-35)/4×10^-2

H= 196W.

The electric power = Heat current =196W

The electric power is the magnitude of heat current

6 0

2 years ago

As a train enters the station it slows down from 40 m/s to a 10 m/s in 5 seconds

lora16 [44]

Answer:

See the answers below.

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f}=v_{o}-a*t$

where:

Vf = final velocity = 10 [m/s]

Vo = initial velocity = 40 [m/s]

t = time = 5 [s]

a = acceleration [m/s²]

Now replacing:

$10=40-a*5\\40-10=a*5\\30=5*a\\a=6[m/s^{2}]$

Note: The negative sign in the above equation means that the velecity is decreasing.

2)

To solve this second part we must use the following equation of kinematics.

$v_{f}^{2} =v_{o}^{2} -2*a*x\\$

where:

x = distance [m]

$(10)^{2} =(40)^{2} -2*6*x\\100=1600-12*x\\12*x=1600-100\\12*x=1500\\x=125[m]$

7 0

2 years ago

A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 500 V . The rat

max2010maxim [7]

Answer:

Explanation:

Rate of dissipation of energy at resistor

= I² R = 296

current I² = 296/R = 296 / 300

I = 0.9933 A.

Impedence Z = V / I = 500 / .9933

= 503 ohm.

B ) Let it be V

voltage across resistance = 300 x .9933 = 298 v

Now 500² = 298² + V²

V = 401 v

C) Power factor = R / Z

=300 / 503

= 0.596

6 0

3 years ago