1.1x+1.2x-5.4=-10
11/10x+12/10x-54/10=10
11x/2.5+2^2-1*3/5x-3^3/5=-10
(11x)+2(2*3x)+2(-3^3)/2*5=-10
11x+2(6x)+2(-27)/2*5=-10
11x+2*6x-2*27/2*5=-10
11x+12x-54/2*5=-10
23x-54/2*5=-10
23x-54=-100
23x=-46
23x/23=-46/23
x=-2*23/23
x=-2
Answer:
-30(3+2w)
(-9-6w) ⋅ 10
−20(4.5 + 3w)
Step-by-step explanation:
Answer:
Step-by-step explanation:
remeber is (x,y) so it will be like this 
7x³ = 28x is our equation. We want its solutions.
When you have x and different powers, set the whole thing equal to zero.
7x³ = 28x
7x³ - 28x = 0
Now notice there's a common x in both terms. Let's factor it out.
x (7x² - 28) = 0
As 7 is a factor of 7 and 28, it too can be factored out.
x (7) (x² - 4) = 0
We can further factor x² - 4. We want a pair of numbers that multiply to 4 and whose sum is zero. The pairs are 1 and 4, 2 and 2. If we add 2 and -2 we get zero.
x (7) (x - 2) (x + 2) = 0
Now we use the Zero Product Property - if some product multiplies to zero, so do its pieces.
x = 0 -----> so x = 0
7 = 0 -----> no solution
x - 2 = 0 ----> so x = 2 after adding 2 to both sides
x + 2 = 0 ---> so = x - 2 after subtracting 2 to both sides
Thus the solutions are x = 0, x = 2, x = -2.
