Enter the fraction in simplest form. 8/14

In a class of students, the following data table summarizes how many students have a cat or a dog. What is the probability that

solniwko [45]

The probability that a student who does not have a dog has a cat is 7/10.

<h3>What is the probability?</h3>

Probability determines the chances that a random event would happen. The odds that the random event would happen lies between 0 and 1.

The probability that a student who does not have a dog has a cat = number of students that do not have a dog but has a cat / total number of students that do not own a dog

= 7/10.

To learn more about probability, please check: brainly.com/question/13234031

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6 0

2 years ago

In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en

jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

Step(i):-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in Swahili language

n(S) = 125

The probability that the fluent in Swahili language

$P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333$

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in English language

$P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9$

n(E∩S) = 95

The probability that the fluent in English and Swahili

$P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633$

Step(ii):-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

= 0.833+0.9-0.633

= 1.1

Final answer:-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0

3 years ago

Lisa spends $8.65 each week on school lunches. How much money does Lisa spend on school lunches in 16 weeks? *

FrozenT [24]

Answer:

Lisa spends $138.40 on school lunches in 16 weeks.

Step-by-step explanation:

You have to multiply 8.65 by 16, since 8.65 is how much money Lisa spends each week for lunch, then you multiply by 16 since the problem calls for 16 weeks, then you get your final answer of $138.40.

3 0

3 years ago

Read 2 more answers

The population of Clayton is

tiny-mole [99]

35,000+6,370= 41,370

8 0

3 years ago

Rewrite the expression in z to the n power. The expression I was given is: 1 over z to the negative 1 half power.

12345 [234]

Answer:

The equivalent expression is;