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Serggg [28]
3 years ago
11

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a s

mall patch of light on the far wall. Having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. It appears that the central maximum is about 3 cm across, and you estimate that the distance from the window shade to the wall is about 3 m.
Estimate the average wavelength of the sunlight (in nm).
Physics
1 answer:
Vaselesa [24]3 years ago
5 0

Answer:

The average wavelength of the sunlight is 550 nm

Explanation:

The average wavelength of the sulight is:

\lambda _{ave}=\frac{\lambda _{i}+\lambda _{f}}{2}

λi = initial wavelength of the sun = 400 nm

λf = final wavelength of the sun = 700 nm

Replacing:

\lambda _{ave}=\frac{400+700}{2} =550nm

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What does kinetic energy do when it go up a hill?what do potential energy do when it does up a hill?
Artist 52 [7]

Answer:

Kinetic energy decreases as you go up hill

Potential energy increases as you go up hill

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It is important that your muscles are very warm when doing this type of stretching.
MaRussiya [10]

Answer:

ballistic stretching

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Read 2 more answers
A student measures the mass 8cm block of brown sugar to be 12.9g. what is the density of the brown sugar.
antoniya [11.8K]

Correction

A student measures the mass <em><u>8cm3</u></em> block of brown sugar to be 12.9g. what is the density of the brown sugar

Answer:

1.6\ g/cm^{3}

Explanation:

Density is defined as mass per unit volume of an object expressed as \rho=\frac {m}{v} where \rho is the density, m is the mass of sugar and v is the volume of the sugar. Considering that the volume is given as 8cm3 for sugar then we substitute this for v and mass of 12.9 g we substitute for g then the density will be

\rho=\frac {12.9 g}{8 cm3}=1.6125\ g/cm^{3}\approx 1.6\ g/cm^{3}

8 0
3 years ago
An Atwood machine is constructed using a hoop with spokes of negligible mass. The 2.3 kg mass of the pulley is concentrated on i
Sergeu [11.5K]

Answer:

a = 2.77~{\rm m/s^2}

Explanation:

Since the pulley has a mass concentrated on its rim, the pulley can be considered as a ring.

The moment of inertia of a ring is

I = mr^2 = (2.3)(23.5\times 10^{-2})^2 = 0.127

The mass on the left is heavier, that is the pulley is rotating counterclockwise.

By Newton's Second Law, the net torque is equal to moment of inertia times angular acceleration.

\tau = I \alpha

Here, the net torque is the sum of the weight on the left and the weight on the right.

\tau = m_1gR - m_2gR = (1.65)(9.8)(23.5\times 10^{-2}) - (1)(9.8)(23.5\times 10^{-2}) = 1.497~{\rm Nm}

Applying Newton's Second Law gives the angular acceleration

\tau = I\alpha\\1.497 = 0.127\alpha\\\alpha = 11.78~{\rm rad/s^2}

The relation between angular acceleration and linear acceleration is

a = \alpha R

Then, the linear acceleration of the masses is

a = 11.78 \times 23.5\times 10^{-2} = 2.77~{\rm m/s^2}

5 0
3 years ago
An automobile moving along a straight track changes its velocity from 40 m/s to 80 m/s in a distance of 200 m. What is the (cons
Nata [24]

Answer:

Dear Kaleb

Answer to your query is provided below

Acceleration of the vehicle is 12m/s^2

Explanation:

Explanation for the same is attached in image

8 0
3 years ago
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