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adell [148]
3 years ago
13

An object is projected from the ground with an upward speed of ų m/s has a speed of 23m/s when it is at a height of 5m above the

ground .Use work energy principle to determine the initial speed u.​
Physics
1 answer:
vovikov84 [41]3 years ago
6 0

Answer:

25.08m/s

Explanation:

mgh1 + 0.5mv1² = mgh2 + 0.5mv2²

h1 = 0m

v1 = u

h2 = 5m

v2 = 23m/s

putting the values into the formula above;

m(10)(0) + 0.5m(u²) = m(10)(5) + 0.5m(23²)

0 + 0.5mu² = 50m + 264.5m

0.5mu² = 314.5m

dividing through by m

0.5u² = 314.5

u² = 629

u = <u>2</u><u>5</u><u>.</u><u>0</u><u>8</u><u>m</u><u>/</u><u>s</u>

<u>Theref</u><u>ore</u><u>,</u><u> </u><u>the</u><u> </u><u>init</u><u>ial</u><u> </u><u>speed</u><u> </u><u>"</u><u>u</u><u>"</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u>m</u><u>/</u><u>s</u>

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Answer:

x = 400 [m]

Explanation:

To solve this problem we must use the following kinematics equations, first, we find the final speed, and then we proceed to find the distance traveled.

v_{f}=v_{i} +(a*t)\\

where:

Vf = final velocity [m/s]

Vi = initial velocity = 15 [m/s]

a = acceleration = 5 [m/s^2]

t = time = 10 [s]

Note: the positive sign in the Equation indicates that the car is accelerating, i.e. its speed is increasing.

<u>Now replacing</u>

Vf = 15 + (5*10)

Vf = 65 [m/s]

Now using the second equation:

v_{f} ^{2}= v_{i} ^{2}+(2*a*x)

where:

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x = (65^2 - 15^2)/ (2*5)

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8 0
4 years ago
A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a very light rope that goes over an ideal pulley. If the
AleksAgata [21]

Answer:

acceleration = 2.4525‬ m/s²

Explanation:

Data: Let m1 = 3.0 Kg, m2 = 5.0 Kg, g = 9.81 m/s²

Tension in the rope = T

Sol: m2 > m1

i) for downward motion of m2:

m2 a = m2 g - T

5 a = 5 × 9.81 m/s² - T  

⇒ T = 49.05‬ m/s² - 5 a     Eqn (a)‬

ii) for upward motion of m1

m a = T - m1 g

3 a = T - 3 × 9.8 m/s²

⇒ T =  3 a + 29.43‬ m/s²   Eqn (b)

Equating Eqn (a) and(b)

49.05‬ m/s² - 5 a = T =  3 a + 29.43‬ m/s²

49.05‬ m/s² - 29.43‬ m/s² = 3 a + 5 a

19.62 m/s² = 8 a

⇒ a = 2.4525‬ m/s²

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3 years ago
How does the wave period relate to the frequency of a wave?
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Answer:

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Hiro does not see a puddle of liquid on the lab table and accidentally touches the liquid. What should Hiro do next?
lys-0071 [83]

Answer: Option (B) is the correct answer.

Explanation:

It is advised that while conducting an experiment in a laboratory, always perform it under the supervision of your teacher.

When Hiro accidentally touches the liquid then he should immediately tell his teacher about it so that timely precaution can be taken to avoid any damage or side effect. Also, Hiro should rinse his hand in the sink because it will neutralize or decrease the effect of spilled liquid on his skin.

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