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adell [148]
2 years ago
13

An object is projected from the ground with an upward speed of ų m/s has a speed of 23m/s when it is at a height of 5m above the

ground .Use work energy principle to determine the initial speed u.​
Physics
1 answer:
vovikov84 [41]2 years ago
6 0

Answer:

25.08m/s

Explanation:

mgh1 + 0.5mv1² = mgh2 + 0.5mv2²

h1 = 0m

v1 = u

h2 = 5m

v2 = 23m/s

putting the values into the formula above;

m(10)(0) + 0.5m(u²) = m(10)(5) + 0.5m(23²)

0 + 0.5mu² = 50m + 264.5m

0.5mu² = 314.5m

dividing through by m

0.5u² = 314.5

u² = 629

u = <u>2</u><u>5</u><u>.</u><u>0</u><u>8</u><u>m</u><u>/</u><u>s</u>

<u>Theref</u><u>ore</u><u>,</u><u> </u><u>the</u><u> </u><u>init</u><u>ial</u><u> </u><u>speed</u><u> </u><u>"</u><u>u</u><u>"</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u>m</u><u>/</u><u>s</u>

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he correct answers are a, b

Explanation:

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in general this phenomenon occurs for small angles, for which we can write

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un

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Let's do the calculation for constructive interference

         d y / L = m λ

the distance between maximum clos is and

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this is the position of each maximum, the distance between two consecutive maximums

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examining this equation if the wavelength decreases the value of y also decreases

the same calculation for destructive interference

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again when it decreases the decrease the distance

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7 0
3 years ago
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