A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. What is the magnitude and direction of the
1 answer:
Answer: A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. Then the magnitude and direction of the student's total displacement will be 87.32 m along the direction of AD or in east-south direction.
Explanation: To find the correct answer, we need to know about the Displacement of a body in motion.
<h3>What is displacement of a body in motion?</h3>- The displacement is the shortest distance between initial and final positions of a body.
- It's a vector quantity, and can positive, negative, or zero.
- The magnitude of displacement is less than or equal to the distance travelled.
- At first, we can draw a diagram showing the motion of the body.
- From the diagram, the displacement of the body will be equal to the distance between point A and D.
- To solve this, we can use Pythagoras theorem.
Thus, from the above calculations, we can conclude that, the displacement of the body will be equal to 87.32 m along the direction of AD or in east-south direction.
Learn more about the Displacement here:
#SPJ4
You might be interested in
The mass of the bird is 0.32 kg.
<u>Explanation:</u>
Gravitational potential energy, the energy exhibited by an object at rest due to the influence of gravitational force. So the increase in distance of object from the surface of earth leads to increase in the gravitational potential energy. Thus,
So, as the gravitational potential energy is given as 2033 J and the position of bird placed on the tall tower is 639 m away from the bottom, then the mass (m) of the bird can be found as below.
So, finally we get the bird's mass as,
m of bird = 0.32 kg