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Galina-37 [17]
3 years ago
13

Which of the following statements are true concerning the creation of magnetic fields? Check all that apply. Check all that appl

y. A permanent magnet creates a magnetic field at all points in the surrounding region. A moving electric charge creates a magnetic field at all points in the surrounding region. A distribution of electric charges at rest creates a magnetic field at all points in the surrounding region. An electric current in a conductor creates a magnetic field at all points in the surrounding region. A single stationary electric charge creates a magnetic field at all points in the surrounding region.
Physics
1 answer:
Andreas93 [3]3 years ago
8 0
<h3><u>Answer;</u></h3>
  • A moving electric charge creates a magnetic field at all points in the surrounding region.
  • An electric current in a conductor creates a magnetic field at all points in the surrounding region.
  • A permanent magnet creates a magnetic field at all points in the surrounding region.
<h3><u>Explanation;</u></h3>
  • A magnetic field can be created by running electricity through a wire. All magnetic fields are created by moving charged particles. it is important to also note that charged particles create magnetic fields only when they are moving.
  • The strength of the magnetic field generated or created is proportional to the amount of current flowing through the wire. Thus, increasing the current increases the strength of the magnetic field.
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What's the mass show the work?
Alja [10]
You do this one just like the other one that I just solved for you.

For this one ...

The density of the object is 2.5 gm/cm³.
We know that every cm³ of it we have contains 2.5 gm of mass.
We have to find out how many cm³ we have.

The question tells us:  We have  2.0 cm³.

Each cm³ of space that the object occupies contains 2.5 gm of mass.

So the 2.0 cm³ that we have contains (2 x 2.5 gm) = 5 gms.
That's the mass of our object.
6 0
3 years ago
provides some pertinent background for this problem. A pendulum is constructed from a thin, rigid, and uniform rod with a small
gavmur [86]

Answer:

the period of the physical pendulum is 0.498 s

Explanation:

Given the data in the question;

T_{simple = 0.61 s

we know that, the relationship between T and angular frequency is;

T = 2π/ω ---------- let this be equation 1

Also, the angular frequency of physical pendulum is;

ω = √(mgL / I ) ------ let this equation 2

where m is mass of pendulum, L is distance between axis of rotation and the center of gravity of rod and I  is moment of inertia of rod.

Now, moment of inertia of thin uniform rod D is;

I = \frac{1}{3}mD²

since we were not given the length of the rod but rather the period of the simple pendulum, lets combine this three equations.

we substitute equation 2 into equation 1

we have;

T = 2π/ω OR T = 2π/√(mgL/I) OR T = 2π√(I/mgL)

so we can use I = \frac{1}{3}mD² for moment of inertia of the rod

Since center of gravity of the uniform rod lies at the center of rod

so that L =  \frac{1}{2}D.

now, substituting these equations, the period becomes;

T = 2π/√(I/mgL) OR T = 2\pi \sqrt{\frac{\frac{1}{3}mD^2 }{mg(\frac{1}{2})D } } OR T = 2π√(2D/3g )  ----- equation 3

length of rod D is still unknown, so from equation 1 and 2 ( period of pendulum ),

we have;

ω_{simple = 2π/T_{simple OR  ω_{simple = √(g/D) OR  ω_{simple = 2π√( D/g )  

so we simple solve for D/g and insert into equation 3

so we have;

T = √(2/3) × T_{simple

we substitute in value of T_{simple

T = √(2/3) × 0.61 s

T = 0.498 s

Therefore, the period of the physical pendulum is 0.498 s

 

8 0
2 years ago
Anyone who scuba dives is advised not to fly within the next 24 h because the air mixture for diving can introduce nitrogen into
Katyanochek1 [597]

Answer:

Explanation:

Let pressure at surface of earth be P Pa.  

pressure at height of 8.1 km in air can be calculated as follows .

pressure due to column of air of 8.1 km height

= h d g , h is height , d is density of air and g is acceleration due to gravity

= 8.1 x 1000 x .87 x 9.8 = 6.9 x 10⁴ Pa .

pressure at the height of 8.1 km

= P - 6.9 x 10⁴ Pa

Pressure due to  column  of 16 m in the sea

= h d g

16 x 1000 x 9.8

= 15.68 x 10⁴ Pa .

Pressure at depth of 16m

= P + 15.68 x 10⁴

pressure difference between points at height of 8.1 km and pressure at point 16 m deep

=  P + 15.68 x 10⁴ -  P +  6.9 x 10⁴ Pa

= 22.58 x 10⁴ Pa .

3 0
3 years ago
If a person wants to move a heavy box across the room, what is required to get the box in motion? apply any force apply a force
garik1379 [7]
If a person want to move a <span>heavy box across the room, he must apply a force that is greater than starting frictional force acted on the heavy box in order to get the box in motion. the frictional force is equal to coefficient of friction times the normal force, and normal force is approximately the weight of the object. so the force that must be applied must be greater than the wieght of the object.</span>
4 0
3 years ago
Read 2 more answers
Calculate the power transfer when a pump moves 50kg of water through a vertical height of 8meters in 5seconds (take g =10meters
Vika [28.1K]

Hi there!

Recall the following relationships:

W = \Delta U = mg\Delta h\\\\P = \frac{W}{t}

W = Work (J)

U = Potential Energy (J)

m = mass (kg)

g = acceleration due to gravity (9.8 m/s²)

h = height (m)

t = time (s)

Begin by calculating the work:

W = 50(10)(8) = 4000 J

Now, divide by the time to solve for power:

P = \frac{4000}{5} = \boxed{800W}

**W is the unit for power (Watts).  Be careful not to get the two confused.

4 0
2 years ago
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