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Galina-37 [17]
3 years ago
13

Which of the following statements are true concerning the creation of magnetic fields? Check all that apply. Check all that appl

y. A permanent magnet creates a magnetic field at all points in the surrounding region. A moving electric charge creates a magnetic field at all points in the surrounding region. A distribution of electric charges at rest creates a magnetic field at all points in the surrounding region. An electric current in a conductor creates a magnetic field at all points in the surrounding region. A single stationary electric charge creates a magnetic field at all points in the surrounding region.
Physics
1 answer:
Andreas93 [3]3 years ago
8 0
<h3><u>Answer;</u></h3>
  • A moving electric charge creates a magnetic field at all points in the surrounding region.
  • An electric current in a conductor creates a magnetic field at all points in the surrounding region.
  • A permanent magnet creates a magnetic field at all points in the surrounding region.
<h3><u>Explanation;</u></h3>
  • A magnetic field can be created by running electricity through a wire. All magnetic fields are created by moving charged particles. it is important to also note that charged particles create magnetic fields only when they are moving.
  • The strength of the magnetic field generated or created is proportional to the amount of current flowing through the wire. Thus, increasing the current increases the strength of the magnetic field.
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Answer:

Answer labeled B : 2,304,000 N

Explanation:

Recall the formula for the electric force:

F_e=9\,\,10^9\,  \,  \frac{q_1*q_2}{d^2} \\F_e=9\,\,10^9\,  \,  \frac{8\,10^{-4}*8\,10^{-4}}{0.05^2} \\F_e=2,304,000\,\,N

which agrees with answer B provided.

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A hot-air balloonist, rising vertically with a constant speed of 5.00 m/s releases a sandbag at the instant the balloon is 40.0
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Answer:

Y = 40.94m

Explanation:

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Y = Yo + Vo*t-\frac{g*t^2}{2}

Replacing these values:

Yo = 40m     Vo = 5m/s     g = 9.81m/s^2     t = 0.25s

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If you wish to take a picture of a bullet traveling at 500 m/s, then a very brief flash of light produced by an RC discharge thr
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Answer:

Resistance in the flash tube, R=3.97\times 10^{-3}\ \Omega

Explanation:

It is given that,

Speed of the bullet, v = 500 m/s

Distance between one RC constant, d = 1 mm = 0.001 m

Capacitance, C=503\ \mu F=503\times 10^{-6}\ F

The time constant of RC circuit is given by :

\tau=RC

R is the resistance in the flash tube

R=\dfrac{\tau}{C}..........(1)

Speed of the bullet is given by total distance divided by total time taken as :

v=\dfrac{d}{\tau}

\tau=\dfrac{d}{v}

\tau=\dfrac{0.001}{500}

\tau=0.000002\ s

Equation (1) becomes :

R=\dfrac{0.000002}{503\times 10^{-6}}

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So, the resistance in the flash tube is 3.97\times 10^{-3}\ \Omega. Hence, this is the required solution.

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3 years ago
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