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damaskus [11]
3 years ago
5

Answer the following. (a) What is the surface temperature of Betelgeuse, a red giant star in the constellation of Orion, which r

adiates with a peak wavelength of about 970 nm? K (b) Rigel, a bluish-white star in Orion, radiates with a peak wavelength of 145 nm. Find the temperature of Rigel's surface. K
Physics
1 answer:
bagirrra123 [75]3 years ago
6 0

Answer:

(a) T = 2987.6 k

(b) T = 19986.2 k

Explanation:

The temperature of a star in terms of peak wavelength can be given by Wein's Displacement Law, which is as follows:

T = \frac{0.2898\ x\ 10^{-2}\ m.k}{\lambda_{max}}

where,

T = Radiated surface temperature

\lambda_{max} = peak wavelength

(a)

here,

\lambda_{max} = 970 nm = 9.7 x 10⁻⁷ m

Therefore,

T = \frac{0.2898\ x\ 10^{-2}\ m.k}{9.7\ x\ 10^{-7}\ m}

<u>T = 2987.6 k</u>

(b)

here,

\lambda_{max} = 145 nm = 1.45 x 10⁻⁷ m

Therefore,

T = \frac{0.2898\ x\ 10^{-2}\ m.k}{1.45\ x\ 10^{-7}\ m}

<u>T = 19986.2 k</u>

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An excited atom decays to its ground state and emits a photon of green light. If instead the atom decays to an intermediate stat
scoundrel [369]

Answer:

the light emitting must be of greater wavelength

Explanation:

For this exercise we must use the Planck equation

             E = h f

And the speed of light

            c = λ f

            f = c / λ

We replace

            E = h c / λ

The wavelength of the green light is of the order of 500 nm, let's calculate the energy

          E = 6.63 10⁻³⁴  3 10⁸ /λ

          E = 1,989 10⁻²⁵ /λ

          λ = 500 nm = 500 10⁻⁹ m

          E = 1,989 10⁻²⁵ / 500 10⁻⁹

          E = 3,978 10⁻¹⁹ J

That is the energy of the transition for a transition is an intermediate state the energy must be less, this implies that the wavelength must increase. For the explicit case of a state with half of this energy

            E_{int} = E / 2

             E_{int} = 3,978 10⁻¹⁹ / 2 = 1,989 10⁻¹⁹

Let's clear and calculate

           λ = h c / E

           λ = 1,989 10⁻²⁵ / 1,989 10⁻¹⁹

           λ = 1 10⁻⁶ m

Let's reduce to nm

          λ = 1000 nm

This wavelength is in the infrared region

the light emitting must be of greater wavelength

8 0
3 years ago
Along a horizontal snow-covered track, a sled, of mass m = 105 kg, slides by the action of a horizontal force of 230 N. The coef
Andrew [12]

Answer:

Explanation:

The only thing I can figure you need here is the accleration of the sled. The equation we need to find this is Newton's Second Law that says that sum of the forces acting on an object is equal to the object's mass times its acceleration. For us, that looks like this because of the friction working against the sled:

F - f = ma but of course it's much more involved than that simple equation! We have the F value as 230 N, and we have the mass as 105, but we do not have the frictional force, f, and we need it to solve for a in the above equation. We know that

f = μF_n where μ is the coefficient of friction, and F_n is the normal force, aka weight of the object. We will use the coefficient of friction and find the weight in order to fill in for f:

F_n=mg so

F_n=(105)(9.8) so the weight of the sled is

F_n= 1.0 × 10³ with the correct number of sig dig there. Now to find f:

f = (.025)(1.0 × 10³) so

f = 25 to the correct number of sig fig. Now on to our "real" equation:

F - f = ma and

230 - 25 = 105a. We have to do the subtraction first, round, and then divide since the rules for addition and subtraction are different from the rules for dividing and multiplying.

230 - 25 will round to the tens place giving us 210. Then

210 = 105a. 210 has 2 sig figs in it while 105 has 3, so we will divide and round to 2 sig fig:

a = 2.0 m/sec²

3 0
3 years ago
What is a mixture in science class
Veseljchak [2.6K]
A mixture is 2 or more different elements not bonded together
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6 0
3 years ago
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Anna71 [15]

Except A. Lava cooling

6 0
3 years ago
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sveta [45]

Answer:

4.5g/cm^3

Explanation:

Here, Mass(m)=67.5g

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Now, According to formula,

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                         =67.5/15

                         =4.5g/cm^3

8 0
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