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3 years ago

Could you guys tell me whether the photo represents a balanced or unbalanced equation

Physics

1 answer:

NARA [144]3 years ago

6 0

Answer:

that is preatty balenced m8

Explanation:

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What is the current of the ammeter?

DaniilM [7]

Answer:

.6 A

Explanation:

V = IR

V/R = I

12/20 = I = .6 A

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2 years ago

Read 2 more answers

A car and a motorcycle start from rest at the same time on a straight track, but the motorcycle is 25.0 m behind the car. The ca

sergeinik [125]

Answer:

t = 8.45 sec

car distance d = 132.09 m

bike distance d = 157.08 m

Explanation:

GIVEN :

motorcycle is 25 m behind the car , therefore distance need to covered by bike to overtake car is 25+ d, when car reache distance d at time t

for car

by equation of motion

$d = ut + \frac{1}{2}at^2$

u = 0 starting from rest

$d = \frac{1}{2}at^2$

$t^2 = \frac{2d}{a}$

for bike

$d+25 = 0 + \frac{1}{2}*4.40t^2$

$t^2= \frac{d+25}{2.20}$

equating time of both

$\frac{2d}{a} = \frac{d+25}{2.20}$

solving for d we get

d = 132 m

therefore t is $= \sqrt{\frac{2d}{a}}$

$t = \sqrt{\frac{2*132}{3.70}}$

t = 8.45 sec

each travelled in time 8.45 sec as

for car

$d = \frac{1}{2}*3.70 *8.45^2$

d = 132.09 m

fro bike

$d = \frac{1}{2}*4.40 *8.45^2$

d = 157.08 m

7 0

3 years ago

When a 109 dB sound wave comes through an open window of area 0.485 m2, how much acoustic energy passes through the window in a

Ksju [112]

Answer:

57dB

Explanation:

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3 years ago

Which type of mirror would you use to cook a hot dog and why?

alexandr1967 [171]

As long as it’s a good mirror then any one of them is fine bc at the end of the day i’m getting a hot dog

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2 years ago

What fraction of the total energy of a SHO is kinetic when the displacement is one third the amplitude

Bas_tet [7]

Answer:

The fraction of kinetic energy to the total energy is $\frac{K}{T}=\frac{8}{9}$ .

Explanation:

displacement is one third of the amplitude.

Let the amplitude is A.

x= A/3

The kinetic energy of the body executing SHM is

$K = 0.5 mw^2(A^2 - x^2)\\\\K = 0.5 m w^2 \left ( A^2 -\frac{A^2}{9} \right )\\\\K = 0.5 mw^2\times \frac{8A^2}{9}......(1)$

The total energy is

$T =0.5 mw^2A^2 ..... (2)$

Divide (1) by (2)

$\frac{K}{T}=\frac{8}{9}$

5 0

3 years ago

Could you guys tell me whether the photo represents a balanced or unbalanced equation​

Could you guys tell me whether the photo represents a balanced or unbalanced equation