Answer: 3.21 N
![Specific\hspace{1mm} gravity = \frac {Density\hspace{1mm}of\hspace{1mm}substance}{Density\hspace{1mm} of \hspace{1mm}water}](https://tex.z-dn.net/?f=%20Specific%5Chspace%7B1mm%7D%20gravity%20%3D%20%5Cfrac%20%7BDensity%5Chspace%7B1mm%7Dof%5Chspace%7B1mm%7Dsubstance%7D%7BDensity%5Chspace%7B1mm%7D%20of%20%5Chspace%7B1mm%7Dwater%7D)
![\Rightarrow Density \hspace{1mm}of\hspace{1mm}substance= 2.32\times 1000\hspace{1mm} kg/m^3 = 2320\hspace{1mm}kg/m^3\\ Mass =Density\times volume\\ \Rightarrow 2320 \hspace{1mm} kg/m^3\times 8.64 \hspace{1mm}in^3\times \frac {1.64\times10^{-5} m^3}{1\hspace{1mm}in^3}=0.328 kg](https://tex.z-dn.net/?f=%5CRightarrow%20Density%20%5Chspace%7B1mm%7Dof%5Chspace%7B1mm%7Dsubstance%3D%202.32%5Ctimes%201000%5Chspace%7B1mm%7D%20kg%2Fm%5E3%20%3D%202320%5Chspace%7B1mm%7Dkg%2Fm%5E3%5C%5C%20Mass%20%3DDensity%5Ctimes%20volume%5C%5C%20%5CRightarrow%202320%20%5Chspace%7B1mm%7D%20kg%2Fm%5E3%5Ctimes%208.64%20%5Chspace%7B1mm%7Din%5E3%5Ctimes%20%5Cfrac%20%7B1.64%5Ctimes10%5E%7B-5%7D%20m%5E3%7D%7B1%5Chspace%7B1mm%7Din%5E3%7D%3D0.328%20kg)
For weight, we will multiply by ![g=9.8 m/s^{-2}](https://tex.z-dn.net/?f=%20g%3D9.8%20m%2Fs%5E%7B-2%7D)
![weight= 0.328\times9.8=3.21\hspace{1mm}N](https://tex.z-dn.net/?f=weight%3D%200.328%5Ctimes9.8%3D3.21%5Chspace%7B1mm%7DN)
Hence, the rock would weigh 3.21 N.
Answer:
I only speak English
Explanation:
I'm sorry can you type it in English
M = 7.0 kg, the mass of the groceries
h = 1.2 m, the elevation of the bag of groceries
The bag of groceries moves a constant velocity over the 2.7-m room.
At constant velocity, there is no applied force, and the kinetic energy remains constant.
At an elevation of 1.2 m, there is an increase in PE (potential energy) given by
V = m*g*h
= (7.0 kg)*(9.8 m/s²)*(1.2 m)
= 82.32 J
The change in PE is equal to the work done.
Answer: 82.3 J