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zaharov [31]
3 years ago
10

At a stoplight, a truck traveling at 15 m/s passes a car as it starts from rest. The truck travels at constant velocity and the

car accelerates at 3 m/s^2. How much time does the car take to catch up to the truck?
Physics
1 answer:
Art [367]3 years ago
4 0
The time that the car take to catch up to truck would be :

1/2 ar^2  = vt

1/2 (3) t^2 = 15t

1.5  t^2  =  15t

t ^2    =   10s

Hope this helps
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So the area under a velocity time graph is distance or displacement, if you have done calculus yet you will understand that if you take the integral of a velocity function then you end up with displacement. Thats for later understanding however.

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Since our area is 10 meters lets alter our formula a bit to fit the situation:

Our base here is time and our height is velocity so:

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t = Δx / 0.5v

Now lets plug all that in:

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Hope this helped!

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-- If the graph shows distance vs time, and the acceleration is a
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6 0
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