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zaharov [31]
4 years ago
10

At a stoplight, a truck traveling at 15 m/s passes a car as it starts from rest. The truck travels at constant velocity and the

car accelerates at 3 m/s^2. How much time does the car take to catch up to the truck?
Physics
1 answer:
Art [367]4 years ago
4 0
The time that the car take to catch up to truck would be :

1/2 ar^2  = vt

1/2 (3) t^2 = 15t

1.5  t^2  =  15t

t ^2    =   10s

Hope this helps
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The law of universal gravitation states that a gravitational force exists between all objects in the universe. This force is dir
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Answer: D. it has been demonstrated to be without exception under certain stated conditions.

Explanation:

A <u>Law</u> is an affirmation (something established) based on repeated long-term observation of a phenomenon that has been studied and verified.  

That is: A law is present in all known theories and therefore is considered universal. In addition, a law can not be refuted, nor changed, because its precepts have been proven through various studies.  

<u>Unlike theory</u>, which is the set of rules and principles that describe and explain a particular phenomenon and <u>is subject to changes as new evidence emerges that gives meaning to it.  </u>

Then, based on what is explained above, the law of universal gravitation is a statement that exists because it was rigorously tested and verified, therefore it can not be refuted.

3 0
3 years ago
El peso de María es de 617,4 N. Si en dos meses pierde 2,5 Kg de masa, ¿cuál será su nuevo peso?
NeTakaya
Two hundred and thirsty years
5 0
4 years ago
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For a ∆x of 0.1mm, what is ∆px, the uncertainty in the transverse momentum of a photon passing through a slit (where uncertainty
Colt1911 [192]

Answer:

0.53\times 10^{-30}kgms^{-1}

Explanation:

Uncertainty principle say that the position and momentum can not be measured simultaneously except one relation which is described below,

\Delta x\Delta p=\frac{h}{4\pi }

Given that the uncertainty in x is 0.1 mm.

Therefore,

\Delta p=\frac{6.626\times 10^{-34} }{4\times 3.14\times 1\times 10^{-4}m }\\\Delta p=0.53\times 10^{-30}kgms^{-1}

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6 0
3 years ago
When bouncing a ball, the bouncing motion results in the ball ____________.
yan [13]

Answer:

B) changing position

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Thus, When bouncing a ball, the bouncing motion results in the ball changing position.

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3 years ago
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In an old-fashioned amusement park ride, passengers stand inside a 4.9-m-diameter hollow steel cylinder with their backs against
Viefleur [7K]

Answer:

24.07415 rpm

Explanation:

\mu = Coefficient of friction = 0.63

v = Velocity

d = Diameter = 4.9 m

r = Radius = \frac{d}{2}=\frac{4.9}{2}=2.45\ m

m = Mass

g = Acceleration due to gravity = 9.81 m/s²

Here the frictional force balances the rider's weight

f=\mu F_n

The centripetal force balances the weight of the person

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Velocity is given by

v=\omega r\\\Rightarrow \omega=\frac{v}{r}\\\Rightarrow \omega=\frac{6.17656}{2.45}\\\Rightarrow \omega=2.52104\ rad/s

Converting to rpm

2.52104\times \frac{60}{2\pi}=24.07415\ rpm

The minimum angular speed for which the ride is safe is 24.07415 rpm

4 0
3 years ago
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