Answer:
∠x = 90°
∠y = 58°
∠z = 32°
Step-by-step explanation:
he dimensions of the angles given are;
∠B = 32°
Whereby ΔABC is a right-angled triangle, and the square fits at angle A, we have;
∠A = 90°
∠B + ∠C = 90° which gives
32° + ∠C = 90°
∠C = 58°
∠x + Interior angle of the square = 180° (Sum of angles on a straight line)
∠x + 90° = 180°
∠x = 90°
∠x + ∠y + 32° = 180° (Sum of angles in a triangle)
90° + ∠y + 32° = 180°
∠y = 180 - 90° - 32° = 58°
∠y + ∠z + Interior angle of the square = 180° (Sum of angles on a straight line)
58° + ∠z +90° = 180°
∴ ∠z = 32°
∠x = 90°
∠y = 58°
∠z = 32°
Answer:
D) 3
Step-by-step explanation:
It is halfway the length of Y and W. 6-3= 3
Note:
Pls notify me if my answer is incorrect for the other users that will see this response. Thank you.
<em>-kiniwih426</em>
Answer:
c. Rational
because → whole numbers are positive and Starts from 0 so not whole number
Integers can be negative and positive
Examples of numbers that are not integers are: -1.43, 1 3/4, 3.14, . 09, and 5,643.1.
Irrational number that cannot be written in p/q
but -2.4 written in p/q = -24/100
<h3>so c. Rational Number is correct</h3>
The correct answer is option B. i.e. the experimental probability is 3% greater than the theoretical probability<span>
The </span>theoretical Outcomes are: HH HT TH TT
Then, the probability of getting HH = 1/4 = 0.25 = 25%
Now, Experimental Outcomes : <span>HH=28 HT=22 TH=34 TT=16
Total number of outcomes = 28+22+34+16 = 100
</span>Then, the probability of getting HH = 28/100 = 0.28 = 28%
Thus, <span>the experimental probability is 3% greater than the theoretical probability</span>
The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft
<h3>How to maximize area?</h3>
Let the length of the rectangular area be x feet
Let the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 320 square feet
y = 320/x -----(1)
Cost to fence the three sides = $6 per foot
Therefore cost to fence one length and two width of the rectangular area
= 6(x + 2y)
Similarly cost to fence the fourth side = $13 per foot
So, the cost of the remaining length = 13x
Total cost to fence = 6(x + 2y) + 13x
Cost (C) = 6(x + 2y) + 13x
C = 6x + 12y + 13x
C = 19x + 12y
From equation (1),
C = 19x + 12(320/x)
C' = 19 - 3840/x²
At C' = 0, we have;
19 - 3840/x² = 0
19 = 3840/x²
19x² = 3840
x² = 3840/19
x = √(3840/19)
x = 14.22 ft
y = 320/14.22
y = 22.5 ft
Read more about Maximization of Area at; brainly.com/question/13869651
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