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REY [17]
3 years ago
5

The function s(t) = vt + h – 0.5at2 represents the height of an object, s, in feet, above the ground in relation to the time, t,

in seconds, since the object was thrown into the air with an initial velocity of v feet per second at an initial height of h feet and where a is the acceleration due to gravity (32 feet per second squared). A baseball player hits a baseball 5 feet above the ground with an initial velocity of 70 feet per second. About how long will it take the baseball to hit the ground? A) 2 seconds B) 3 seconds C) 4 seconds D) 5 seconds
Physics
1 answer:
leonid [27]3 years ago
6 0

Answer:

C) 4 seconds

Explanation:

The height of an object is given by the following formula:

s(t)=h+vt-0.5at^2\\\\a=32ft/s

To find the flight time you equal the height s to zero:

0=5ft+70\frac{ft}{s}\ t-0.5(32\frac{ft}{s^2})t^2\\\\0=5ft+70\frac{ft}{s}\ t-16\frac{ft}{s^2}t^2

Then, you have a quadratic equation of the form:

ax^2+bx+c

you use the quadratic formula in order to find the roots of the polynomial:

t_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\a=-16\\\\b=70\\\\c=5\\\\t_{1,2}=\frac{-70\pm \sqrt{(70)^2-4(-16)(5)}}{2(-16)}\\\\t_{1,2}=\frac{-70\pm 72.24}{-32}\\\\t_1=4.44s\approx4s\\\\t_2=-007s

you take the positive value of t because this has physical meaning.

Hence:

the time is C) 4 seconds

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To better visualize things, let's repair the equation a little

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Let's replace

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This is the exact expression for weight change with height, but let's look at its values ​​for some reasonable heights h = 6300 m (very high mountain)

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Therefore, the negligible weight reduction, therefore, for practical purposes the weight does not change with the height of the mountain on Earth

The correct answer is a

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