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alexandr402 [8]
3 years ago
5

Why did the chicken cross the road

Physics
2 answers:
agasfer [191]3 years ago
8 0
To get to the other side
Mashutka [201]3 years ago
6 0

Answer:

it wanted to go vegan

Explanation:

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a child is swinging on swing, describe what happens to both the kinectic energy and potential enegry of the child as she swings
Igoryamba

Answer:

The K.E is maximum when the child is at the vertical position and the P.E is maximum at the extreme deviated position from the vertical.

Explanation:

  • A child is swinging on swing up and down has both kinetic and potential energy.
  • The total mechanical energy of the system is conserved throughout the system. At any instant the total mechanical energy is given by,

                                      E = K.E + P.E

  • The K.E is maximum when the child is at the vertical position.
  • The P.E is maximum at the extreme deviated position from the vertical.
  • And when K.E is maximum P.E becomes minimum and vice versa as per the law of conservation of energy.
5 0
3 years ago
From the 1780s to the late 1800s, people thought the amount of land and resources in the West was limited
Sonbull [250]

Answer:true

Explanation:

7 0
3 years ago
Which of the following is not a an example of dissipated energy?
Kaylis [27]
Which of the following is not a an example of dissipated energy?
b. kinetic

When energy is changed from one form to another, ____.

b. all of the energy can be accounted for

4 0
3 years ago
If the distance between slits on a diffraction grating is 0.50 mm and one of the angles of diffraction is 0.25°, how large is th
Trava [24]

Answer:

-  path differnce = 2.18*10^-6

-  1538 lines

Explanation:

- The path difference for the waves that produce the pattern of diffraction, is given by the following formula:

path\ difference\ = dsin\theta           (1)

d: separation between slits = 0.50mm = 0.50*10^-3 m

θ: angle of a diffraction = 0.25°

Then, the path difference is:

path\ difference\ =(0.50*10^{-3}m)sin(0.25\°)=2.18*10^{-6}m

- The maximum number of bright lines are calculated by using the following formula:

m\lambda = dsin\theta           (2)

m: order of the bright

λ: wavelength = 650nm

The maximum bright is calculated for an angle of 90°:

m=\frac{(0.50*10^{-3}m)sin90\°}{650*10^{-9}m} \approx 769

The maxium number of bright lines are twice the previous result, that is, 1538 lines

8 0
3 years ago
Read 2 more answers
Railroad car A, with mass 6275 kg, is traveling east at 6.5 m/s along a straight track. It strikes railroad car B, with mass 515
LekaFEV [45]

The speed of A and B immediately after collision is 5.28m/s

<u>Explanation:</u>

Mass of A is 6275kg

Speed of A is 6.5m/s

Mass of B is 5155kg

Speed of B is 3.8m/s

Track is frictionless.

A and B stick together.

speed of attached A and B = ?

mₐsₐ + mᵇsᵇ = (mₐ + mb) s

6275 X 6.5 + 5155 X 3.8 = ( 6275 + 5155) X s\\\\s = \frac{40787.5 + 19589}{11430}\\ \\s = \frac{60376.5}{11430}\\ \\s = 5.28m/s

Therefore, The speed of A and B immediately after collision is 5.28m/s

4 0
3 years ago
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