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KatRina [158]
4 years ago
9

What is the landing velocity of an object that is dropped from a height of 49 m?

Physics
1 answer:
Tems11 [23]4 years ago
8 0
We can use the formula Vf^2= Vi^2 + 2ad.

So,
Vi = 0 since we are dropping the object 

Therefore,

Vf^2 = 2 (9.8) (49)

You can do the calculator work.
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A bus traveled down Interstate 35 at a speed of 75 km/h for 4 hours. How many kilometers was the bus speeding?
vesna_86 [32]

Answer:

300 kilometers

Explanation:

75 km x 4  = 300 km

8 0
3 years ago
How does Newton's three laws of motion apply to the egg drop project
BabaBlast [244]
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Read 2 more answers
Objects in space are moving at a constant velocity in a straight line.
tigry1 [53]

Answer:

C

Explanation:

An object in motion will stay in motion unless acted on by a net positive or negative force.

For answer A. If the object were to be in an orbit, it would inevitably accelerate due to it being acted on by the gravitational force from the object it is orbiting. At different points in the orbit, the object will move at different speeds and continuously transfer between kinetic and potential energy.

For answer B. The object would would not stop their motion. In order for the object to lose energy, it would have to transfer it through friction or through its interaction with a gravitational field.

For answer D. No energy is "required" to maintain constant motion unless the object is willingly fighting against a resistive force like friction or a graviational well.

8 0
2 years ago
Air is a good medium for sound waves because it is
Paul [167]

Answer:

air does not have a modulus of rigidity.

Explanation:

Since air is completely elastic medium, that is, it does not have a modulus of rigidity, therefore sound waves in air are longitudinal.

4 0
2 years ago
Find the magnitude of acceleration (ft/s^2) a person experiences when he or she is texting and driving 58mph, hits a wall, and c
SVEN [57.7K]

Answer:

350 ft/s²

Explanation:

First, convert mph to ft/s.

58 mi/hr × (5280 ft/mi) × (1 hr / 3600 s) = 85.1 ft/s

Given:

v₀ = 85.1 ft/s

v = 0 ft/s

t = 0.24 s

Find: a

v = at + v₀

a = (v − v₀) / t

a = (0 ft/s − 85.1 ft/s) / 0.24 s

a = -354 ft/s²

Rounded to two significant figures, the magnitude of the acceleration is 350 ft/s².

7 0
3 years ago
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