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IgorC [24]
3 years ago
11

What wavelength ? should the astrophysicist look for to detect a transition of an electron from the n=7 to the n=3 level?

Physics
1 answer:
Veseljchak [2.6K]3 years ago
7 0
Using the Debroglies equation,energy can be found,as 1.9773*10*-9
then, energy* wave length= hc
c is the speed of light and is the planks constant.
wave length =1.006*10*-16 m
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As you move from left to right across a period the number of valances electrons
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The valence electrons increase as you move left to right.
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A ball rolls down a ramp for 15 seconds. If the initial velocity of the ball was 0.8m/s and the final velocity was 7m/s, what wa
iren [92.7K]
Acceleration = (change in speed) / (time for the change)

Change in speed = (ending speed) - (starting speed)

                            =  (7.0 m/s)  -  (0.8 m/s)  =  6.2 m/s

Time for the change  =  15 seconds

Acceleration  =  (6.2 m/s) / (15 sec)

                      =   (6.2/15)  m/s²

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3 years ago
The radiation per unit area from the Sun reaching the earth is 1400 W/m2 , approximately the amount of radiative power per unit
natka813 [3]

Answer:

83.2 W/m^2

Explanation:

The radiation per unit area of a star is directly proportional to the power emitted, which is given by Stefan-Boltzmann law:

P=\sigma A T^4

where

\sigma is the Stefan-Boltzmann constant

A is the surface area

T is the surface temperature

So, we see that the radiation per unit area is proportional to the fourth power of the temperature:

I \propto T^4

So in our problem we can write:

I_1 : T_1^4 = I_2 : T_2^4

where

I_1 = 1400 W/m^2 is the power per unit area of the present sun

T_1 = 5800 K is the temperature of the sun

I_2 is the power per unit area of sun X

T_2 = 2864 K is the temperature of sun X

Solving for I2, we find

I_2 = \frac{I_1 T_2^4}{T_1^4}=\frac{(1400 W/m^2)(2864 K)^4}{(5800 K)^4}=83.2 W/m^2

6 0
3 years ago
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Leni [432]

Answer:

the first one is D

Explanation:

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Alika [10]

Answer:

Where is the comments??

Explanation:

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3 years ago
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