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Ipatiy [6.2K]
3 years ago
11

Newton’s law of gravity says the gravitational force between two objects is proportional to:

Physics
1 answer:
Nat2105 [25]3 years ago
3 0

Answer:

Mass of the object or earth

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How much work must be done in the car to slow it from 100km/h to 50km/h
Brilliant_brown [7]

Answer:

-96.465m joule

Explanation:

Let m = mass of the car and v1 = initial velocity and v2 = final velocity

Given.

Initial velocity = 100 km/h

final velocity = 50 km/h

What is work done in the car to slow it from 100km/h to 50km/h?

v1=100km/h=27.78m/s

v2=50km/h=13.89m/s

The work done in the car to slow it from v1 to v2.

w=Δk

w=k2-k1

w= \frac{1}{2}m(v2)^{2}- \frac{1}{2}m(v1)^{2}

w=\frac{1}{2} m(v2-v1)^{2}

w=\frac{1}{2}\times m(13.89 -27.78)^{2}

w=\frac{1}{2}\times m(-13.89)^{2}

w=\frac{1}{2}\times m\times (-192.93)

w=-96.465m joule.

Therefore, the work done is -96.465m joule

7 0
3 years ago
An airplane starts from rest and accelerates at a constant 3.00 m/s2
katrin2010 [14]

Answer:600 m

Explanation:

6 0
3 years ago
Which best describes the weak nuclear force? It is weaker than the gravitational force, with a greater range than the weak nucle
labwork [276]

Weak nuclear force is weaker than the strong nuclear force with a smaller range than the electromagnetic force.

It acts between fermions with spin 1/2 basically quarks and leptons. It has a range of 10⁻¹⁸ meters.

Option 1 is incorrect. It is stronger than the gravitational force.

Option 2 is incorrect. It is weaker than the electromagnetic force.

Option 3 is incorrect. It has a smaller range than the strong nuclear force.

7 0
4 years ago
Read 2 more answers
8. Chemical weathering occurs more rapidly in what kind of climates?
Lady bird [3.3K]

I think it's b..................

5 0
4 years ago
Read 2 more answers
A box-shaped metal can has dimensions 6 in by 2 in by 12 in high. All of the air inside the can is removed with a vacuum pump. A
leva [86]

Answer:

a) The total force is 4659.8 N

b) The gauge pressure is 50764 Pa

Explanation:

Given:

Pressure inside = 0

Patm = pressure outside = 1.013x10⁵Pa

Pressure difference = ΔP = 1.013x10⁵ - 0 = 1.013x10⁵Pa

a) The area is equal:

A=12*6=72in^{2} =0.046m^{2}

The force is:

F=delta-P*A=1.013x10^{5} *0.046=4659.8N

b) The gauge pressure at the bottom is equal:

P=\rho gh

Where:

ρ = density = 1000 kg/m³

h = 17 ft = 5.18 m

Replacing:

P=1000*9.8*5.18=50764Pa

8 0
3 years ago
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