If this charged soot particle is now isolated (that is, removed from the electric field described in the previous part), what wi
1 answer:
The magnitude of the electric field due to the particle at the given distance is .
The electric field strength of a charged particle is the force per unit charge in the given field.
The electric field strength of a charge is given as;
where;
- k is Coulomb's constant
- q is the charge
- r is the distance
Thus, the magnitude of the electric field due to the particle at the given distance is .
Learn more about electric field here: brainly.com/question/14372859
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Answer:
(a) The initial speed required is 13116 m/s
(b) The escape speed is 10394 m/s
This problem involves the application of newtons laws of gravitation. The forces in action here are conservative and as a result mechanical energy is conserved.
The full calculation can be found in the attachment below.
Explanation:
In both parts (a) and (b) the energy conservation equation were used. Assumption was made that when the object is very far from the planet the distance from the planet's center approaches infinity and the gravitational potential energy approaches zero.
The calculation can be found below.
Remember that the total velocity of the motion is the vector sum of the velocity you would have in still water and the stream. Always place the vectors carefully to be able to come up with an accurate sum vector.
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