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QveST [7]
3 years ago
6

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Mathematics
1 answer:
shusha [124]3 years ago
6 0

Answer:convergent

Step-by-step explanation:

Given

Improper Integral I is given as

I=\int_{-\infty}^{0}1000e^xdx

I=1000=\int_{-\infty}^{0}e^xdx

integration of e^x is e^x

I=1000\times \left [ e^x\right ]^{0}_{-\infty}

I=1000\times I=\left [ e^0-e^{-\infty}\right ]

I=1000\times \left [ e^0-\frac{1}{e^{\infty}}\right ]

I=1000\times 1=1000

so the integration converges to 1000 units  

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