On a coordinate plane, 2 right triangles are shown. The first triangle has points A (negative 1, 3), B (negative 1, 1), C (3, 1)
2 answers:
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Answer:
3775 in²
Step-by-step explanation:
The surface area of the ramp :
Area of rectangle = 20 * 23 = 460 in²
Area of rectangle = 20 * 23 = 460 in²
Area of rectangle = 25 * 23 = 575 in²
Bottom rectangle = 60 * 23 = 1380 in²
For the trapezium: (front and rear)
1/2 (base 1 + base 2) * height
Base total = 20+ 20+ 20= 60
1/2(60)*15 = 450 in²
Total surface Area :
(460 + 460 + 575 + 1380 + 450 + 450) in² = 3775 in²
<u>Answer-</u>
<u>Solution-</u>
The given data as follows,
After converting all the percentages and fractions to decimal, we can compare them all.
For converting percentages to decimal to divide the number by 100, so
Then converting the fraction into decimal,
As, all the numbers are converted into decimal, now comparing all the numbers,
Answer:
Test statistic t = 5.25
P-value = 0.000002 (one-tailed test)
Step-by-step explanation:
This is a hypothesis test for the population mean.
The claim is that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.
Then, the null and alternative hypothesis are:
The significance level is 0.05.
The sample has a size n=49.
The sample mean is M=8.5.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=√s^2=√4=2.
The estimated standard error of the mean is computed using the formula:
Then, we can calculate the t-statistic as:
The degrees of freedom for this sample size are:
This test is a right-tailed test, with 48 degrees of freedom and t=5.25, so the P-value for this test is calculated as (using a t-table):
As the P-value (0.000002) is smaller than the significance level (0.05), the effect is significant.
The null hypothesis is rejected.
There is enough evidence to support the claim that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.