Answer:
2.10x10⁻⁹ moles of Si, 143.7 moles of CCl₄, 3.49x10²⁴ atoms
Explanation:
These is the relation:
NA (6.02x10²³) ⇒ 1 mol of particles (it can be, atoms or molecules)
This are the rule of three:
NA of atoms occupies 1 mol of Si
1.27x10¹⁵ atoms will occupy (1.27x10¹⁵ .1 ) / NA = 2.10x10⁻⁹ moles of Si
NA of molecules are contained in 1 mol of CCl₄
8.65x10²⁵ molecules are contained in (8.65x10²⁵ .1)/ NA = 143.7 moles
1 mol of Ca has NA atoms
5.80 moles of Ca will have (5.80 . NA) = 3.49x10²⁴
Answer:
373.15 K
Explanation:
Given data:
Temperature in degree Celsius = 100°C
Temperature in kelvin scale = ?
Solution:
To convert the degree Celsius into kelvin scale we add the given degree Celsius into 273.15.
100°C +273.15 = 373.15 K
Answer:
c
Explanation:
it is c because that is the andwer
Amount Remaining Years #half lives
100g 0 0
50 g 100 1
25g 200 2
A. Each is found outside the nucleus
