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QveST [7]
3 years ago
14

What is the difference between absolute value negative 3 and -3

Mathematics
1 answer:
PolarNik [594]3 years ago
3 0
They both have the same absolute value. Their absolute value would be 3
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Write 224% as a fraction or mixed number in the simplest form.
OlgaM077 [116]
Since it’s 224% just put it over 100 and now convert it to a mixed number with would be 2 24/100 and now simplified which is 2 6/25
So the answer is 2 6/25
6 0
2 years ago
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The scatter plot below shows the high temperature for one day and the number of coats in the theater coat check on that same day
Setler [38]

Answer:

the number of coats in the coat check will most likely decrease if the temperatures decrease.

Step-by-step explanation:

Im guessing this answer: Number of coats in the coat check will decrease because the graph shows negative association

But it could also be this answer: Number of coats in the coat check will decrease because the graph shows positive association

I think the graph shows a negative association because when the temperature goes down, the coat check goes down as well

6 0
3 years ago
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Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
4 years ago
How do i covert a fraction into a decimal.
Olenka [21]

Answer:

By dividing the top number by the bottom.

Step-by-step explanation:

ummmmm

3 0
3 years ago
What is the slope of the line through (2,-2)(2,−2)left parenthesis, 2, comma, minus, 2, right parenthesis and (9,3)(9,3)left par
Alecsey [184]

Answer:

Slope=5/7

Step-by-step explanation:

Slope=Δy/Δx=(3-(-2)) /(9-2)=5/7

3 0
3 years ago
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