Question

Larry , Moe, and Curly are pushing on a 25 kg crate. The crate is sitting on a horizontal floor, and the coefficient of kinetic friction between the floor and the crate is 0.25. Larry pushes to the right with a force of 400 N. Moe pushes to the left with a force of 250 N. Curly pushes straight downward on the crate with a force of 150 N. What is the acceleration of the crate

Answer 1

Answer:

2 m/s².

Explanation:

The forces acting on the crate have been shown in the figure below.

Net force acting on the crate in the horizontal direction = 400 - 250 = 150 N towards right.

For the forces of vertical direction we can write,

Normal force = 150 + Mg = 150 + 250 = 400 N (here g = 10 m/s² have been taken)

The magnitude of frictional force that will act on the crate = μ × Normal force

So, Frictional force = 0.25 × 400 = 100 N

Thus, the net force that will cause acceleration in the crate will be

Force in the right direction - frictional force

= 150 - 100 = 50 N

As we know,

Acceleration = $\frac{Force}{Mass}$ =  $\frac{50}{25}$ = 2 m/s²

So, the net acceleration in the crate will be 2 m/s².