Larry , Moe, and Curly are pushing on a 25 kg crate. The crate is sitting on a horizontal floor, and the coefficient of kinetic
friction between the floor and the crate is 0.25. Larry pushes to the right with a force of 400 N. Moe pushes to the left with a force of 250 N. Curly pushes straight downward on the crate with a force of 150 N. What is the acceleration of the crate
1 answer:
Answer:
2 m/s².
Explanation:
The forces acting on the crate have been shown in the figure below.
Net force acting on the crate in the horizontal direction = 400 - 250 = 150 N towards right.
For the forces of vertical direction we can write,
Normal force = 150 + Mg = 150 + 250 = 400 N (here g = 10 m/s² have been taken)
The magnitude of frictional force that will act on the crate = μ × Normal force
So, Frictional force = 0.25 × 400 = 100 N
Thus, the net force that will cause acceleration in the crate will be
Force in the right direction - frictional force
= 150 - 100 = 50 N
As we know,
Acceleration = =
= 2 m/s²
So, the net acceleration in the crate will be 2 m/s².
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Explanation:
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