3 years ago

If you view a complete free body diagram of a moving object, what two apects of the body's motion will the diagram show?

Physics

1 answer:

aliya0001 [1]3 years ago

5 0

In a completed free body diagram, the diagram should show the magnitude and direction of the body's motion.

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2. A girl whose mass is 55kg stands on a spring weighing machine inside a lift. When the lift starts to ascend, its acceleration

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Answer:

Explanation:

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3 years ago

What is the number of electrons that move past a point in a wire carrying 500 A of current in 4.0 minutes

mr Goodwill [35]

The current is defined as the amount of charge Q that passes through a given point of a wire in a time $\Delta t$ :
$I= \frac{Q}{\Delta t}$
Since I=500 A and the time interval is
$\Delta t=4.0 min=240 s$
the charge is
$Q=I \Delta t=(500 A)(240 s)=1.2 \cdot 10^5 C$

One electron has a charge of $q=1.6 \cdot 10^{-19}C$ , therefore the number of electrons that pass a point in the wire during 4 minutes is
$N= \frac{Q}{q}= \frac{1.2 \cdot 10^5 C}{1.6 \cdot 10^{-19}C}=7.5 \cdot 10^{23}$ electrons

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3 years ago

A flea jumps straight up to a maximum height of 0.550 m . what is its initial velocity v0 as it leaves the ground?

Alexxx [7]

Since my givens are x = .550m [Vsub0] = unknown
[Asubx] = =9.80

[Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0]

[Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0])

Vsubx is the final velocity, which at the max height is 0, and Xsub0 is just 0 as that's where it starts so I just plug the rest in

0^2 = [Vsub0x]^2 + 2[-9.80]*(.550)

0 = [Vsub0x]^2 -10.78

10.78 = [Vsub0x]^2

Sqrt(10.78) = 3.28 m/s

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3 years ago

How to find the total displacement of an object ?

OLga [1]

Answer:

it can be calculated by measuring the final distance away from a point, and then subtracting the initial distance

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Whos the best character in assassination classroom

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Karma, and sensei. Maybe nagisa

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3 years ago

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