The infrasound waves were at just the right ________________ to vibrate the human eye. no frikin links!!!

Find the magnitude of the resultant force and the angle it makes with the positive x-axis. (Let |a| = 22 lb and |b| = 16 lb. Rou

SVEN [57.7K]

Incomplete question as the angle between the force is not given I assumed angle of 55°.The complete question is here

Two forces, a vertical force of 22 lb and another of 16 lb, act on the same object. The angle between these forces is 55°. Find the magnitude and direction angle from the positive x-axis of the resultant force that acts on the object. (Round to one decimal places.)

Answer:

Resultant Force=33.8 lb

Angle=67.2°

Explanation:

Given data

Fa=22 lb

Fb=16 lb

Θ=55⁰

To find

(i) Resultant Force F

(ii)Angle α

Solution

First we need to represent the forces in vector form

$\sqrt{x} F_{1}=22j\\ F_{2}=u+v\\F_{2}=16sin(55)i+16cos(55)j\\F_{2}=16(0.82)i+16(0.5735)j\\F_{2}=13.12i+9.176j$

Total Force

$F=F_{1}+F_{2}\\ F_{2}=22j+13.12i+9.176j\\F_{2}=13.12i+31.176j$

The Resultant Force is given as

$|F|=\sqrt{x^{2} +y^{2} }\\|F|=\sqrt{(13.12)^{2} +(31.176)^{2} }\\ |F|=33.8lb$

For(ii) angle

We can find the angle bu using tanα=y/x

So

$tan\alpha =\frac{31.176}{13.12}\\ \alpha =tan^{-1} (\frac{31.176}{13.12})\\\alpha =67.2^{o}$

7 0

4 years ago

In some proton accelerators, proton beams are directed toward each other for head-on collisions. Suppose that in such an acceler

ipn [44]

Answer:

a) 0.9995c

b) 5641MeV

c) 91670 MeV

Explanation:

(a) The speed of approach is given by the formula:

$u=\frac{v_1+v_2}{1+\frac{v_1v_2}{c}}=\frac{2(0.9898c)}{1+\frac{(0.9898)^2c^2}{c^2}}=0.99995c$

(b) the kinetic energy is given by:

$E_k=m_0c^2[\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}-1]$

by replacing c=3*10^8m/s, m_0=1.67*10^{-27}kg we obtain:

$E_k=5641MeV$

(c) in the rest frame of the other proton we have:

$E_k=m_0c^2[\frac{1}{\sqrt{1-\frac{u^2}{c^2}}}-1]$

by replacing we get

$E_k=91670MeV$

hope this helps!!

7 0

3 years ago

Bats use sound to sense objects by sending out short ultrasound pulses and listening for the echo off the object. A. Sketch the

ivann1987 [24]

Answer:

B. t = 0.250s

Explanation:

A. An image with the sketch of the bat emitting a sound, which reflects on a surface and return to the bat is attached below.

B. In order to calculate the time that the pulse emitted by the bat, return to the bat, you first calculate the time that pulse takes to arrive to the object.

You use the following formula:

$x=vt$ (1)

x: distance to the object = 43m

t: time = ?

v: speed of sound beat = 343 m/s

You solve the equation (1) for t:

$t=\frac{x}{v}=\frac{43m}{343m/s}=0.125s$

The time on which the bat hears the echo is twice the value of t, that is:

$t'=2(0.125s)=0.250s$

The time on which bat heart the echo of its sound, from the moment on which bat emitted it, is 0.250s

6 0

3 years ago

Difference between regular and irregular object.

DaniilM [7]

<h2>Answer:</h2><h2>Regular object</h2>

Those substance which have fixed geometrical shape are called regular object.
For example: books,pencils, basketball etc.

<h2>Irregular object</h2>

Those substance which do not have geometrical shape are called irregular object.
For example: a piece of stone,a broken piece of brick,leaf etc.

Hope this helps....

Good luck on your assignment.....

5 0

3 years ago

What type of energy conversion occurs at the moment fireworks explode?

Paladinen [302]

chemical energy converts into light, heat and sound energy

6 0

4 years ago

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