1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,
A = L*H = 12*6 = 72 cm^2
3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).
Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2
4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.
Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
Answer:
Attached is what the graph should look like
Step-by-step explanation:
Answer:
The answer is one.
Step-by-step explanation:
4y=-20+3x and 4y=13.6x-20
so
-20+3x=13.6x-20
3x=13.6x
3=13.6 so it is wrong and system doesn’t have solution
Answer:
x=13 y=10 z=3 d) 260
Step-by-step explanation:
vertex angles are congruent so you can set them equal to each other and solve
and then a straight like adds up to 180 so 180-(7(x-3)+5y)= your missing angle and then that angles is congruent to its opposite so 2(5z+15)=60
