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Tom [10]
3 years ago
13

50 Points!

Mathematics
2 answers:
Advocard [28]3 years ago
7 0
Well, 50 points total given, 25 points per user  and 13 bonus for brainliest

anyway


1.
add them equations, the y's will cancel
x+2y=4
<span>3x-2y=4 +</span>
4x+0y=8

4x=8
divide by 4 both sides
x=2
sub back
x+2y=4
2+2y=4
minus 2
2y=2
divide 2
y=1
x=2
y=1
(x,y)
(2,1) is solution


2.
the solution is where they intersect
multiply 2nd equation by 2 and add to first
4x-14y=6
<span>-4x+14y=-6 +</span>
0x+0y=0
0=0
infinite solutions

that is because they are actually the same line
the solutions are (x,y) such that they satisfy -2x+7y=-3 or 4x-14y=6 (same equaiton)
infinite solutions



3.
multiply first equation by 2 and add to first
4x+2y=-6
<span>1x-2y=-4 +</span>
5x+0y=-10

5x=-10
divide by 5 both sides
x=-2
sub bac
x-2y=-4
-2-2y=-4
add 2
-2y=-2
divide by -2
y=1

x=-2
y=1
(x,y)
(-2,1)


4.
coincident means they are the same line
so

we see that we have to multiply 4 by 2 to get 8
multiply top equation by 2
8x+10y=16
8x+By=C
B=10 and C=16


5.
a. false, either 0, 1, or infinity solutions
change the word 'two' to 'one' or 'zero' or 'infinite', or change 'can' into 'can't'

b.false
 'sometimes' to 'always'

c. true

d. false, change 'sometimes' to 'always'


EC
total cost=150
TC=childC+adultC
TC=3c+5a
150=3c+5a


40 tickets, c+a
40=c+a

the equations are
150=3c+5a and
40=c+a

eliminate
multiply 2nd equaton by -3 and ad to first one

150=3c+5a
<span>-120=-3c-3a +</span>
30=0c+2a

30=2a
divide by 2
15=a

sub back
40=c+a
40=c+15
minus 15
25=c

25 children tickets and 15 adult tickets were sold


ANSWERS:

1.
(2,1) is solution

2.
infinite solutions

3.
(-2,1)

4.
B=10 and C=16

5.
a. false,
change the word 'two' to 'one' or 'zero' or 'infinite', or change 'can' into 'can't'

b.false
 'sometimes' to 'always'

c. true

d. false, change 'sometimes' to 'always'

EC
the equations are
150=3c+5a and
40=c+a
25 children tickets and 15 adult tickets were sold
zubka84 [21]3 years ago
7 0
Question 1: 
You should know that the Y on both lines will be crossed out and then you add the X which you will end up with: 
4X = 8 
X = 8/4 = 2 

So, y is: 
2 + 2Y = 4 
2Y = 2 
Y = 1 
Answer is: (2,1) 

Question 2: 
what you should do is to solve the second line for Y, then plug the Y in the Y that is in the first line! 
So Y is equal to: Y = 2/7X - 3/7 
Plug it in: 4X - 14( 2/7X - 3/7) = 6 
Solve for X: X= 5/3 
Now solve for Y: Y= 0.2857142857 
(if you out them in the equations you will get 6)

Question 3: 
Same as the Question 2. Solve for Y. then find the number of X. Then find the answer for Y. 
Answer: X= -11/4 and Y= .625 :)

Question 4: 
4X in the first line, then 8X in the second one. So, you can say that their numbers are multiplied by 2. 
So, B is 10 and C is 16. 

Question 5: 
a. T
b. Always. F
c. T
d. never. F

3c + 5a = 150 
a + c = 40 
these two equations can solve the problem! 
Answer: a = 15 and c= 25 :) 

Have a wonderful day! 
(this question took me more than I expected) 




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Archy [21]
First you have to put like terms together:
bf+af+be+ae
Now you factor the first two terms and then the two last terms:
f(b+a)+e(b+a)
Now you factor even further. By putting what is in parentheses by what is outside the parentheses:
(b+a)(f+e)
What you got is correct as mine is too. I hope this formula helps for future problems:
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3 years ago
Read 2 more answers
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andriy [413]

Answer:

z(max) =  256000  Php

x₁ = 10

x₂ = 110

Step-by-step explanation:

Jogging pants design                Selling Price       Cost    

weekly production

 Design A    x₁                                     2500            1750

  Design B    x₂                                    2100            1200      

1. z ( function is : )

z = 2500*x₁  +  2100*x₂       to maximize

First constraint weekly production

 x₁    +   x₂    ≤  120

Second constraint Budget

1750*x₁  +  1200*x₂   ≤   150000      

Then the model is

z = 2500*x₁  +  2100*x₂       to maximize

Subject to

 x₁    +   x₂    ≤  120

1750*x₁  +  1200*x₂   ≤   150000  

General constraints   x₁  ≥  0           x₂   ≥ 0            both integers

First table

z           x₁           x₂        s₁       s₂      cte

1       -2500      -2100    0       0         0

0          1              1          1        0  = 120

0      1750         1200     0       1   = 150000

Using AtoZmath online solver and after 6 iterations the solution is:

z(max) =  256000  Php

x₁ = 10

x₂ = 110

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7 0
3 years ago
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irakobra [83]

Answer:

a. 114 minutes

b. 48 minutes

Step-by-step explanation:

Given that

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a. if Priya practice violin for 152% as Han Practiced for piano

So the minutes she practice in Violin is

= 75 minutes × 152%

= 114 minutes

Likewise

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So the minutes he practice in Clarinet is

= 75 minutes × 64%

= 48 minutes

The same is to be considered

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