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svetoff [14.1K]
3 years ago
15

A college student realized that he was spending too much money on music. For the remaining 5 months of the year his goal is to s

pend a mean of $⁢50 a month towards music. How much can he spend in December, taking into consideration that in the other 4 months he spent $20 , $⁢75 , $⁢20 , and $⁢90 , respectively? Round your answer to two decimal places, if necessary.
Mathematics
1 answer:
Elodia [21]3 years ago
8 0

the expression for mean in this case is

50 = \frac{1}{5}(d + 20 + 75 + 20 + 90) = \frac{1}{5}(d+205)

with d standing for expenditure in December. Now solve for d:

250 = d + 205\\d = 45

The student has to spend $45 to meet his goal.

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How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and
omeli [17]

Step-by-step explanation:

x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\     (given)

Let us consider :

x_{1} = t_{1} + 1

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x_{3} = t_{3}

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x_{5} = t_{5}

Now, by substituting the above considerations in the above equation, we get:

t_{1} + 1 + t_{2} + t_{3} + t_{4} + t_{5} = 21\\

t_{1}  + t_{2} + t_{3} + t_{4} + t_{5} = 20\\

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then it follows

n = 20

r = 4

then no. of solutions for the eqn = _{r}^{n + r}\textrm{C}

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                                                      = 10626

Answer :

no. of solutions for the eqn 10626

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