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svetoff [14.1K]
3 years ago
15

A college student realized that he was spending too much money on music. For the remaining 5 months of the year his goal is to s

pend a mean of $⁢50 a month towards music. How much can he spend in December, taking into consideration that in the other 4 months he spent $20 , $⁢75 , $⁢20 , and $⁢90 , respectively? Round your answer to two decimal places, if necessary.
Mathematics
1 answer:
Elodia [21]3 years ago
8 0

the expression for mean in this case is

50 = \frac{1}{5}(d + 20 + 75 + 20 + 90) = \frac{1}{5}(d+205)

with d standing for expenditure in December. Now solve for d:

250 = d + 205\\d = 45

The student has to spend $45 to meet his goal.

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250 sheep in a 40-acre pasture.
Number of sheep grazing in each acre.

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Sample 1: 4 → 4/6 = 0.67
Sample 2: 1 → 1/6 = 0.17
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multiply the sample proportion by 1-ρ
Sample 1: 0.67(1-0.67) = 0.67(0.33) = 0.2211
Sample 2: 0.17(1-0.17) = 0.17(0.83) = 0.1411
Sample 3: 1.50(1-1.5) = 1.5(-0.5) = -0.75

divide the result by n. n = 6
Sample 1: 0.2211/6 = 0.03685
Sample 2: 0.1411/6 = 0.02352
Sample 3: -0.75/6 = -0.125

square root of the quotient to get the standard error.
Sample 1: √0.03685 = 0.1919
Sample 2: √0.02352 = 0.1534
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z value 95% confidence 1.96.

Sample 1: 1.96 * 0.1919 = 0.3761 or 37.61% margin of error
Sample 2: 1.96 * 0.1534 = 0.3007 or 30.07% margin of error


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