in a canoe race, a team paddles downstream 480 m in 60 s. The same team makes the trip upstream in 80 s. Find the team's rate in
still water and the rate of the current
1 answer:
480=60(v+s)
480=60v+60s
8=v+s
s=8-v...
480=80(v-s) using s from above we get:
480=80(v-(8-v))
6=v-8+v
6=2v-8
2v=14
v=7, and since s=8-v, s=1
So the rate of the team is 7m/s while the rate of the stream is 1m/s
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