Part 1)
(x²+15x+65)+(2x-5)*(3x+8)
(x²+15x+65)+(6x²+16x-15x-40)
(7x²+16x+25)
the answer Part 1) is the letter B
(7x²+16x+25)
Part 2)
(4x+1)*(3x-4)-(5x²-10x-12)
(4x+1)*(3x-4)-(5x²-10x-12)
(12x²-16x+3x-4)-(5x²-10x-12)
(7x²-3x+8)
the answer Part 2) is the letter D
(7x²-3x+8)
Part 3)
(8x²+19x+4)+(3x+2)*(x-5)
(8x²+19x+4)+(3x²-15x+2x-10)
(11x²+6x-6)
the answer part 3) is the letter A
(11x²+6x-6)
Part 4)
(6x+1)*(3x-7)-(7x²-34x-20)
(18x²-42x+3x-7)-(7x²-34x-20)
(11x²-5x+13)
the answer Part 4) is the letter C
(11x²-5x+13)
C. The range represents the number of users each month for 36 months.
Since O is circumscribed about quadrilateral DEFG, the value of x is equal to: D. 68°.
<h3>What is a supplementary angle?</h3>
A supplementary angle can be defined as two (2) angles or arc whose sum is always equal to 180 degrees. Mathematically, a supplementary angle can be calculated as follows:
Q + R = 180°.
In Geometry, the opposite angles of any cyclic quadrilateral that is inscribed inside a circle always form a supplementary angle. Thus, we would determine the value of x by using the mathematical expression above:
x + 112° = 180°
x = 180° - 112°
x = 68°
Read more on supplementary angle here: brainly.com/question/12542846
#SPJ1
So for this, we will be using synthetic division. To set it up, have the equation so that the divisor is -10 (since that is the solution of k + 10 = 0) and the dividend are the coefficients. Our equation will look as such:
<em>(Note that synthetic division can only be used when the divisor is a 1st degree binomial)</em>
- -10 | 1 + 2 - 82 - 28
- ---------------------------
Now firstly, drop the 1:
- -10 | 1 + 2 - 82 - 28
- ↓
- -------------------------
- 1
Next, you are going to multiply -10 and 1, and then combine the product with 2.
- -10 | 1 + 2 - 82 - 28
- ↓ - 10
- -------------------------
- 1 - 8
Next, multiply -10 and -8, then combine the product with -82:
- -10 | 1 + 2 - 82 - 28
- ↓ -10 + 80
- -------------------------
- 1 - 8 - 2
Next, multiply -10 and -2, then combine the product with -28:
- -10 | 1 + 2 - 82 - 28
- ↓ -10 + 80 + 20
- -------------------------
- 1 - 8 - 2 - 8
Now, since we know that the degree of the dividend is 3, this means that the degree of the quotient is 2. Using this, the first 3 terms are k^2, k, and the constant, or in this case k² - 8k - 2. Now what about the last coefficient -8? Well this is our remainder, and will be written as -8/(k + 10).
<u>Putting it together, the quotient is
</u>