Answer:
250N
Explanation:
Given parameters:
Time = 4s
Momentum = 1000kgm/s
Unknown:
Force = ?
Solution:
To solve this problem, we use Newton's second law of motion;
Ft = Momentum
F is the force
t is the time
So;
F x 4 = 1000kgm/s
F = 250N
If the surface is rough then the average force needed to move the wooden block will be more as the friction between the surfaces will be more.
Hence, the least force will be required on the smoothest surface and the greatest force will be required for the roughest surface.
a) Hence, the order will be: B > D > A > C
b) When the surface is glued then the force of friction will increase. Hence, it will require more force to move the wooden block on the surface. Hence, the more required will be more than 105 N.
<h3>Answer:</h3>
The mechanical advantage would decrease, making the block more difficult to lift.
<h3>Explanation:</h3>
The mechanical advantage in such a setup is the ratio of distance from A to B to the distance from D to B. In this picture, that ratio is less than 1, meaning the advantage of having this setup is less than the advantage of no setup at all.
While the force required to lift the block is increased by this setup, the distance over which that force is applied will be smaller for raising the block to a given height. (Overall, for the same height, more work is required with the lever setup because you're raising part of the mass of the lever as well as the mass of the block.)
Answer:
Part a)

Part b)

Part c)
So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass
Explanation:
Part a)
Let say the collision between Moose and the car is elastic collision
So here we can use momentum conservation


also by elastic collision condition we know that

now we have

now we have

Now loss in kinetic energy of the car is given as


so fractional loss in energy is given as



Part b)
Let say the collision between Camel and the car is elastic collision
So here we can use momentum conservation


also by elastic collision condition we know that

now we have

now we have

Now loss in kinetic energy of the car is given as


so fractional loss in energy is given as



Part c)
So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass
You need to clean and sand wood of any ruff edges