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professor190 [17]
3 years ago
10

A 4.4 kg object is being pushed along a surface, causing it to accelerate at a rate of 1.5 m/s2 . Th e coeffi cient of kinetic f

riction is 0.25. What is the magnitude of the horizontal force being applied to push the object?

Physics
1 answer:
emmasim [6.3K]3 years ago
8 0
Friction = 0.25 * m * g = 10.8
Push = m * a + Friction = 4.4 * 1.5 + 10.8

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URGENT PHYSICS QUESTION WILL GIVE BRAINLIEST
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Answer:

7.2V

Explanation:

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Answer:

t=14.678\times 10^{-3}s

Explanation:

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thus, we have

C\times 0.9E=CE(1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})

or

0.9=1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}

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-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}=-ln(10)

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t=75\times 10^6\ \times\ 85\times 10^{-12}\times ln{10}

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