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stepan [7]
3 years ago
6

Can someone please help me

Physics
2 answers:
Ahat [919]3 years ago
6 0
The third answer. a liter. 
Aleks [24]3 years ago
5 0
The metric unit of volume is the liter.

1 cubic meter = 1,000 liters

A liter looks a lot like a quart.  It's only about 6% bigger than a quart.

The larger-style water bottle that you might buy at the Sebm Lebm store
and carry with you when you're walking is 16.9 ounces ... that's 1/2 liter.

Those big heavy plastic soda bottles that hang around in the fridge
for several days are 2-liter bottles.
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A child slides down a snow‑covered slope on a sled. At the top of the slope, her mother gives her a push to start her off with a
kirill [66]

Answer:

θ = 13.16 °

Explanation:

Lets take mass of child = m

Initial velocity ,u= 1.1 m/s

Final velocity ,v=3.7 m/s

d= 22.5 m

The force due to gravity along the incline plane = m g sinθ

The friction force = (m g)/5

Now from work power energy

We know that

work done by all forces = change in kinetic energy

( m g sinθ - (m g)/5 ) d = 1/2 m v² - 1/2 m u²

(2  g sinθ - ( 2 g)/5 ) d = v² -  u²

take g = 10 m/s²

(20 sinθ - ( 20)/5 ) 22.5 = 3.7² -  1.1²

20 sinθ - 4 =12.48/22.5

θ = 13.16 °

5 0
3 years ago
An ion has 8 protons and 10 electrons. What is the total charge? *
Korolek [52]
The answer is -2 sjs
3 0
3 years ago
A 4.00-kg mass is attached to a very light ideal spring hanging vertically and hangs at rest in the equilibrium position. The sp
Ahat [919]

Answer:

|v| = 8.7 cm/s

Explanation:

given:

mass m = 4 kg

spring constant k = 1 N/cm = 100 N/m

at time t = 0:

amplitude A = 0.02m

unknown: velocity v at position y = 0.01 m

y = A cos(\omega t + \phi)\\v = -\omega A sin(\omega t + \phi)\\ \omega = \sqrt{\frac{k}{m}}

1. Finding Ф from the initial conditions:

-0.02 = 0.02cos(0 + \phi) => \phi = \pi

2. Finding time t at position y = 1 cm:

0.01 =0.02cos(\omega t + \pi)\\ \frac{1}{2}=cos(\omega t + \pi)\\t=(acos(\frac{1}{2})-\pi)\frac{1}{\omega}

3. Find velocity v at time t from equation 2:

v =-0.02\sqrt{\frac{k}{m}}sin(acos(\frac{1}{2}))

5 0
3 years ago
Read 2 more answers
What force is required to give an object with mass 2000 kg an acceleration of 3.5 m/s2
ch4aika [34]
According to Newton's Second Law:
F = m*a = 2000 kg*3.5 m/s^2 = 7000 N
8 0
4 years ago
Read 2 more answers
How can i solve this?
Luba_88 [7]
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3 years ago
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