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3 years ago

In this diagram, which force is represted by L?

Physics

1 answer:

Dmitry [639]3 years ago

8 0

Answer is a) the force caused by the wend nag encountering wind and air.

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A same-size iron ball and wooden ball are dropped simultaneously from a tower and reach the ground at the same time. The iron ba

Papessa [141]

Answer:

momentum of iron ball is greater than wooden ball

Explanation:

when metal ball (iron ball) and wooden drop are drop from same elevation and reaching the ground after same time. at this position the iron ball has greater momentum than wooden ball

we know that momentum is defined as

P=Mv

and we know also that mass of iron ball is greater than mass of wooden ball and they reached on ground at same time and same distance it mean also velocity will be same for both ball. therefore from above relation we have

Miron*V > Mwood*V i.e.

momentum of iron ball is greater than wooden ball

5 0

4 years ago

Nathan is standing 2 feet away from a plane mirror. Hiva is standing 5 feet further than

Viktor [21]

Answer:

They are standing 3 feet away from each other

Explanation:

If Nathan Is standing 2 feet away from the mirror. Then Hiva is standing 7 feet away from the mirror is she is standing 5 feet further than him. They are standing 3 feet away from each other.

3 0

3 years ago

The 1.5-kg collar C starts from rest at A and slides with negligible friction on the fixed rod in the vertical plane. Determine

arlik [135]

Answer:

Explanation:

check attached image for figure, there is supposed to be a figure for this question containing a distance(height of collar at position A) but i will assume 0.2m or 200mm

Consider the energy equilibrium of the system

$U_{A-B}=\bigtriangleup T\\\\F\cos 30°\times h_A - F\sin30°\times h_A + Wh_A=\frac{1}{2}m(v^2_B-v^2_A)\\\\v_B=\sqrt{\frac{2Fh_A(\cos 30° - \sin30°)+mgh_A}{m+v^2_A}}$

Here, F is the force acting on the collar, $h_A$ is the height of the collar at position A, m is the mass of the collar C, g is the acceleration due to gravity, $v_B$ is the velocity of the collar at position B, and $v_A$ is the velocity of the collar at A

Substitute 14.4N for F, 0.2m for $h_A$ , 1.5kg for m, $9.81m/s^2$ for g and 0 for $v_A$

$v_B=\sqrt{\frac{2(14.4\times 0.2(\cos 30° - \sin30°)+1.5\times 9.81\times 0.2}{1.5+0}}\\\\=\sqrt{\frac{6.618}{1.5}}\\\\=4.412m/s$

Therefore, the velocity at which the collar strikes the end B is 4.412m/s

8 0

3 years ago

Displacement vectors of 4 km north, 2 km south, 5 km north, and 5 km south combine to a total displacement of

valentinak56 [21]

south = -(north)

Displacement = (4 km north) + (2 km south) + (5 km north) + (5 km south)

Displacement = (4 km north) - (2 km north) + (5 km north) - (5 km north)

Displacement = (4 - 2 + 5 - 5) km north

<u>Displacement = 2 km north </u>

6 0

3 years ago

You move a 2.5 kg book from a shelf that is 1.2 m above the ground to a shelf that is 2.6 m above the ground. What is the change

Sophie [7]

The change in potential energy of an object is given by
$U=mg \Delta h$
where
m is the mass of the object
g is the gravitational acceleration
$\delta h$ is the increase in altitude of the object

In our problem, $m=2.5 kg$ is the mass of the book, $g=9.81 m/s^2$ and
$\Delta h=2.6 m -1.2 m=1.4 m$ is the increase in altitude of the book, so its variation of potential energy is
$U=mg\Delta h=(2.5 kg)(9.81 m/s^2)(1.4 m)=34.3 J$

8 0

4 years ago