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3 years ago

In this diagram, which force is represted by L?

Physics

1 answer:

Dmitry [639]3 years ago

8 0

Answer is a) the force caused by the wend nag encountering wind and air.

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An electric bell is kept under a bell jar in which a vacuum has been created. Slowly air is introduced in to the jar. What will

Aleks [24]

A. Increase until it reaches it's maximum. Sound travels through air and as the amount of air in the jar increases, the loudness or amplitude of the bell increases until it reaches it's maximum at normal air pressure.

8 0

3 years ago

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A 62.0-kg skier is moving at 6.30 m/s on a frictionless, horizontal, snow-covered plateau when she encounters a rough patch 4.90

Klio2033 [76]

Here are the missing questions:
(a) How fast is the skier moving when she gets to the bottom of the hill?
(b) How much internal energy was generated in crossing the rough patch?
Part A
The initial kinetic energy of the skier is:
$E_{k0}=m\frac{v_0^2}{2}$
Part of this energy is then used to do work against the force of friction. Force of friction on the horizontal surface can be calculated using following formula:
$F_f=mg\mu$
The work is simply the force times the length:
$W_f=F_f\cdot L=mg\mu L$
So when the skier passes over the rough patch its energy is:
$E=E_{k0}-W_f$
When the skier is going down the skill gravitational potential energy is transformed into the kinetic energy:
$E_p=E_{k1}\\ mgh=E_{k1}$
So the final energy of the skier is:
$E_f=E_{k0}-W_f+E_{k1}\\ E_f=m\frac{v_0^2}{2}-mg\mu L+mgh=1856.86$J$
This energy is the kinetic energy of the skier:
$E_f=m\frac{v_f^2}{2}\\ v_f=\sqrt{\frac{2E_f}{m}}=7.74\frac{m}{s}$
Part B
We know that skier lost some of its kinetic energy when crossing over the rough patch. This energy is equal to the work done by the skier against the force of friction.
$E_{int}=W_f\\
E_{int}=mg\mu L=894.1$J$

4 0

4 years ago

1 oto đang có v = 54km /h thì hãm phanh . cđ chậm dần đều đi đc 50m nữa thì dừng lại xác định gia tốc , vận tốc oto sau 2 giây k

madam [21]

Answer:

huh?

Explanation:

I'm so sorry but, i don't get it

3 0

3 years ago

A 77.3 g mass is attached to a horizontal spring with a spring constant of 12.5 N/m and released from rest with an amplitude of

DENIUS [597]

Answer:

speed of the mass is 3.546106 m / s

Explanation:

given data

mass = 77.3 g = 77.3 × $10^{-3}$ kg

spring constant k = 12.5 N/m

amplitude A = 38.9 cm = 38.9 × $10^{-2}$ m

to find out

the speed of the mass

solution

we will apply here conservation energy that is

K.E + P.E = Total energy ..................1

so that Total energy = K.E max = P.E max

we know amplitude so we find out first P.E max that is

PE max = K.E + P.E

(1/2)kA² = (1/2)mv² + (1/2)kx²

kA^² = mv²+ kx²

so here v² will be

v² = k(A² - x²) / m

v = √[(k/m)×(A² - x²)] ............2

here x = (1/2)A so from from 2 equation

v = √[(k/m)×(A² - (A/2)²)]

v = √[(k/m)×(3/4×A²)]

now put all value

v = √[(12.5/ 77.3 × $10^{-3}$ )×(3/4×(38.9 × $10^{-2}$ )²)]

v = 3.546106 m / s

speed of the mass is 3.546106 m / s

6 0

3 years ago

HERES THE ANSWER AND QUESTION

tatyana61 [14]

Answer:

agree

Explanation:

5 0

3 years ago

Read 2 more answers