What is the potential difference across a parallel-plate capacitor whose plates are separated by a distance of 4.0 mm where each
1 answer:
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Answer:
#_electrons = 2 10¹⁰ electrons
Explanation:
For this exercise we can use a direct rule of three proportions rule. If an electron has a charge of 1.6 10⁻¹⁹ C how many electrons have a charge of 3.2 10⁻⁹ C
#_electrons = 3.2 10⁻⁹ ( )
#_electrons = 2 10¹⁰ electrons
The frictional force is 39.4 N
Explanation:
We can solve this problem by applying Newton's 2nd law of motion: in fact, the net force acting on the block is equal to the product between its mass and its acceleration. So we can write
where
is the net force
m is the mass
a is the acceleration
Here we know that the box is moving with constant velocity, so its acceleration is zero:
This means that the net force is also zero:
The net force on the block is given by the applied force, forward, and the frictional force, backward:
where
is the applied force
is the frictional force
Therefore, solving for ,
Learn more about friction:
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